Consider the following user-defined function:
void Quick_Change (int x, int & y)
{
if (x == 0)
y = 10;
else if (y == 0)
x = 10;
}Assume the values in variable A and B are both of int type. How do I find what the values are after execution of the statement Quick_Change(A,B), if the values of A and B are
0 and 5 respectively?
5 and 0 respectively?
5 and 5 respectively?
0 and 0 respectively?
Jump to PostAssuming you mean without using a program, perhaps using pencil and paper to solve each case? The first parameter is passed by value, so it will remain unchanged in the calling function after the function call; the second parameter is passed by reference, so its value may be changed in …
Jump to Posthttp://www.fredosaurus.com/notes-cpp/functions/params.html
Google for function parameters "by reference" and "by value". Once you understand that, this question becomes quite easy.
Jump to PostMaybe this is a little better:
Jump to PostThe
==operator compares for equality.
Assuming you mean without using a program, perhaps using pencil and paper to solve each case? The first parameter is passed by value, so it will remain unchanged in the calling function after the function call; the second parameter is passed by reference, so its value may be changed in the calling function following the function call.
http://www.fredosaurus.com/notes-cpp/functions/params.html
Google for function parameters "by reference" and "by value". Once you understand that, this question becomes quite easy.
either way
what does the "==" mean?
nvm it means equal to
The == operator compares for equality.
yea
Tell me if this is right
0 and 5 respectively? A=0, B=10
5 and 0 respectively? A=10, B=0
5 and 5 respectively? A=5, B=5
0 and 0 respectively? A=10, B=10
Two of them are wrong.
You need to learn by-reference and by-value parameters.
really which two?
You have 1 and 3 right.
I'll give you a quick explanation.
You have two parameter types to your function: by-value and by-reference.
int x is by-value.
int &y is by-reference.
What this basically means is any change made to x within that function is local to that function. It will not change the of the variable A used to call the function.
By-reference means that any change to y within that function will also change the value of the variable B used to call that function.
How about this then
0 and 5 respectively? A=0, B=10
5 and 0 respectively? A=5, B=0
5 and 5 respectively? A=5, B=5
0 and 0 respectively? A=0, B=10
Looks right.
thanks !
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