hi everyone,
I'm trying to write a program that calculates the the fourth sqrt() of an int ..., can someone help me
thnxx
hi everyone,
I'm trying to write a program that calculates the the fourth sqrt() of an int ..., can someone help me
thnxx
hi everyone,
I'm trying to write a program that calculates the the fourth sqrt() of an int ..., can someone help me
thnxx
And where is the product of your efforts?
Remember classics: I'm trying to write a program to hop on the Moon...
And where is the product of your efforts?
Remember classics: I'm trying to write a program to hop on the Moon...
well, i know that i can use the library function double sqrt(double x) to get the sqrt of x, but i don't know how to get the fourth sqrt() of x :'(.
Is your "fourth sqrt()" equal to 1/4 of square root or it's a quadratic root?
Is your "fourth sqrt()" equal to 1/4 of square root or it's a quadratic root?
it equals to to 1/4 sqrt()...
I do not think so, it could be sqrt(sqrt(x)) , or else if it 1/4sqrt(x) , you are supposed to use some iteration formula to calculate an approximate square root of x and then divide it by 4.
I think it's:
pow(number, power)
pow(10, 0.4);
I'm not sure so check it out. It's in <math.h>
I can't understand your troubles. Evidently it's 0.25*sqrt(x)
or sqrt(sqrt(x))
. Or what else? What's a problem?
I can't understand your troubles. Evidently it's
0.25*sqrt(x)
orsqrt(sqrt(x))
. Or what else? What's a problem?
I agree: the fourth root of a number, x, is sqrt(sqrt(x)), or pow(x, 0.25).