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I am creating a tetris-like game. I have decided to use coordinates (x,y) along with a dictionary. Here is a part of the dictionary:

gameTable = {(-5,10):0,(-4,10):0,(-3,10):0,(-2,10):0,(-1,10):0,(0,10):0, (1,10):0, (2,10):0, (3,10):0, (4,10):0, (5,10):0, (-5,9):0, (-4,9):0, (-3,9):0, (-2,9):0, (-1,9):0, (0,9):0, (1,9):0, (2,9):0, (3,9):0, (4,9):0, (5,9):0, (-5,8):0, (-4,8):0, (-3,8):0, (-2,8):0, (-1,8):0, (0,8):0, (1,8):0, (2,8):0, (3,8):0, (4,8):0, (5,8):0...

Notice that they are in proper order.
Now, take a look at what happens when I try to print it:

{(4, -3): 0, (-4, -6): 0, (-1, 0): 0, (-5, 1): 0, (3, -10): 0, (-4, 10): 0, (-5, 3): 0, (0, 4): 0, (-5, -3): 0, (1, 1): 0, (4, 10): 0, (3, 2): 0, (2, 6): 0, (-3, -8): 0, (-4, -3): 0, (-1, -2): 0, (-2, -1): 0, (-4, 4): 0, (2, -10): 0, (2, -7): 0, (-4, -7): 0, (-5, 6): 0, (-1, 3): 0...

It gets out of order.
My main question is:
How do I stop python from ordering this dictionary, if it even is?


Thanks!

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Last Post by Ene Uran
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You have no choice when it comes to ordering dictionaries. If you want it to print nicely then you CAN order gameTable.keys() . Here is how i would do it:

gameTable = {(-5,10):0,(-4,10):0,(-3,10):0,(-2,10):0,(-1,10):0,(0,10):0, (1,10):0, (2,10):0, (3,10):0, (4,10):0, (5,10):0, (-5,9):0, (-4,9):0, (-3,9):0, (-2,9):0, (-1,9):0, (0,9):0, (1,9):0, (2,9):0, (3,9):0, (4,9):0, (5,9):0, (-5,8):0, (-4,8):0, (-3,8):0, (-2,8):0, (-1,8):0, (0,8):0, (1,8):0, (2,8):0, (3,8):0, (4,8):0}
keys = gameTable.keys()
keys.sort()
for key in keys:
    print key
    print gameTable[key]

Hope that helps.

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There is an ordered dictionary module that can be found here. Works just like a regular dictionary but is kept in order.

HTH

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sort() did sort out the dict, but not in the correct order.
So unfortunately, I am forced to use a list which works nicely. :/

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