I am creating a tetris-like game. I have decided to use coordinates (x,y) along with a dictionary. Here is a part of the dictionary:

gameTable = {(-5,10):0,(-4,10):0,(-3,10):0,(-2,10):0,(-1,10):0,(0,10):0, (1,10):0, (2,10):0, (3,10):0, (4,10):0, (5,10):0, (-5,9):0, (-4,9):0, (-3,9):0, (-2,9):0, (-1,9):0, (0,9):0, (1,9):0, (2,9):0, (3,9):0, (4,9):0, (5,9):0, (-5,8):0, (-4,8):0, (-3,8):0, (-2,8):0, (-1,8):0, (0,8):0, (1,8):0, (2,8):0, (3,8):0, (4,8):0, (5,8):0...

Notice that they are in proper order.
Now, take a look at what happens when I try to print it:

{(4, -3): 0, (-4, -6): 0, (-1, 0): 0, (-5, 1): 0, (3, -10): 0, (-4, 10): 0, (-5, 3): 0, (0, 4): 0, (-5, -3): 0, (1, 1): 0, (4, 10): 0, (3, 2): 0, (2, 6): 0, (-3, -8): 0, (-4, -3): 0, (-1, -2): 0, (-2, -1): 0, (-4, 4): 0, (2, -10): 0, (2, -7): 0, (-4, -7): 0, (-5, 6): 0, (-1, 3): 0...

It gets out of order.
My main question is:
How do I stop python from ordering this dictionary, if it even is?


Thanks!

You have no choice when it comes to ordering dictionaries. If you want it to print nicely then you CAN order gameTable.keys() . Here is how i would do it:

gameTable = {(-5,10):0,(-4,10):0,(-3,10):0,(-2,10):0,(-1,10):0,(0,10):0, (1,10):0, (2,10):0, (3,10):0, (4,10):0, (5,10):0, (-5,9):0, (-4,9):0, (-3,9):0, (-2,9):0, (-1,9):0, (0,9):0, (1,9):0, (2,9):0, (3,9):0, (4,9):0, (5,9):0, (-5,8):0, (-4,8):0, (-3,8):0, (-2,8):0, (-1,8):0, (0,8):0, (1,8):0, (2,8):0, (3,8):0, (4,8):0}
keys = gameTable.keys()
keys.sort()
for key in keys:
    print key
    print gameTable[key]

Hope that helps.

There is an ordered dictionary module that can be found here. Works just like a regular dictionary but is kept in order.

HTH

sort() did sort out the dict, but not in the correct order.
So unfortunately, I am forced to use a list which works nicely. :/

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