The problem is A voltage source supplies a load through a resistor. The

voltage source has a rating of 1000 volts and a power rating

of 10000 watts. The resistor is 5 ohms with a power ratings

of 118.975 watts. The resistance of the load may vary

randomly between 200 and 600 ohms. Using 100000 samples

calculate the following:

1-number of times the power rating of the resistor is exceeded

2-average power delivered by source

3-maximum power delivered by source

4-minimum power delivered by source

The output of the program should consist of 4 numbers,

each number being output on a separate line in the order

listed above. The numbers should be output with a precision

of 2. The seed is 259.

Ok im not sure where to plug in the value given but im pretty sure I got the code set up right

```
#include <iostream>
#include <string>
#include <iomanip>
#include <cmath>
#include <stdio.h>
using namespace std;
int main()
{
double a,b,exceded, limit,average, max, min, powerRating, powerDelivered, power;
exceded = 0;
average = 0;
max = 0;
min = 0;
powerRating=(259*400)+200;
for (int i = 0; i < 100000; i++)
{
a = powerRating; //calculated with (rnd*400) + 200 as resistance)
if (a > limit)
{
exceded++;
}
b = powerDelivered;
average += b;
if (b > max)
{
max = b;
}
if (b < min)
{
min = b;
}
average = average / 100000;
cout << "# of times the power rating of the resistor is exceeded:"<<exceded ;
cout <<"Average power:"<<power;
cout <<"Maximum power:"<<max;
cout <<"Minimum power:"<<min;
}
}
```