pre and post increment

[chuppy]

hi..can anyone explain to me?? i am very confused abt this two..

for example;

iint m [] = { 3, 2, 5, 2 };
int k = 0;

System.out.println("(a)" + m[ k++ ];
System.out.println("(a)" + m[ ++k ];
*i compiled..but i dun understand why is the result 3 and 5 respectively???

hopefully u guys can give me more examples and detailed explanation...very confused on the post increment part..thanks a million...

* struggling here..revising for my java exam ..:'(

[javaAddict]

Read the comments

int m [] = { 3, 2, 5, 2 };
int k = 0;

// k has value 0 so it returns 3. THEN k is increased because the ++ is after the variable
System.out.println("(a)" + m[ k++ ];

// k has now value 1

// ++k. The ++ is before the variable so the increase will happen FIRST. So k will become 2. THEN k will "return" its value which is 2
// m[2] = 5
System.out.println("(a)" + m[ ++k ];


// it compiled..but i dun understand why is the result 3 and 5 respectively???

Try running this:

int k = 0;
// first prints then increases
System.out.println("K before the increase: "+ (k++) );
System.out.println("K now: "+ k );

k = 0;
// first increases then prints
System.out.println("K after the increase: "+ (++k) );
System.out.println("K now: "+ k );

[chuppy]

thanks for the explanation...i'll go figure it out.

[chuppy]

one more qn.. what is the difference between

System.out.println("(a)" + (1 + m[k]) );

and

System.out.println("(a)" + 1 + m[k] ) ;

i realised that the output is different..it's 3 and 12 respectively...

what difference does it make because of the additional bracket??

[javaAddict]

First it will calculate what is inside the parenthesis and return it. Then it will concatenate it with the rest: 
System.out.println("(a)" + [B]([/B]1 + m[k][B])[/B] );

// "(a)" + (1 + m[k]) --> "(a)" + (1+2) --> "(a)" + 3 --> (a)3
and 

// no parenthesis. Things will be calculated with the order they appear
System.out.println("(a)" + 1 + m[k] ) ;

//                     [U]String + int[/U]   --> [U]String[/U]       
// "(a)" + 1 + m[k] --> [U]"(a)" + 1[/U] + 2 --> [U]"(a)1"[/U] + 2 --> (a)12

In math they teach us first to calculate the parenthesis.