*
* *
* * *
* * * *
* * * * *
i want code for this.pls giv me the code

Well, it's pretty freaking easy when you don't have to calculate the binomial coefficients. Just two trivial loops if you don't want leading whitespace and three if you do.

>i want code for this.
Then you'd better get started on writing it.

>pls giv me the code
No. And saying "please" isn't going to help because we don't give freebies to cheaters like you. Do it yourself and if you have a real question, we'll help answer it.

#include<iostream.h>
#include<conio.h>
void main()
{
int i,j,n;
cin>>n;
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
cout<<"*";
}
}
getch();
}
commented: Fail (on multiple levels). -4

it does rather depend what language u r using.
but it is a simple loop job where each time you go round the loop (until it exits in this case at five) you just increase the counter by +1 and then print out the '*' multiplied by the counter.

over to u
M

>it does rather depend what language u r using.
I could be wrong, but since this thread is in the C forum, it'd say C is pretty freaking likely to be the language he's using.

>over to u
Don't waste your time. By now this leech has already gotten a failing grade on the homework, and we'll never see him again.

sorry I did n't see (c!) the c forum but I agree there is only one way to program ...do it. I think this thread could be closed!
M