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I have this homework assignment that i need help with and below is the code that i have so far. any help would be appreciated. thank you.


Write a program that tells what coins to give out for any amount of change from 1 cent to 99 cents.
For example, if the amount is 86 cents, the output would be something like the following:

86 cents can be given as 3 quarter(s) 1 dime(s) amd 1 penny(pennies).
Use coin denominations of 25 cents (quarters),
10 cents (dimes) and 1 cent (pennies).
Do not use nickel and half-dollar coins.
Your program will use the following function (amoung others): void computeCoin(int coinValue, int& number, int& amountLeft); /* Preconditions:
0 < coinValue < 100;
0 <= amountLeft < 100.
Postconditions: number has been set equal to the maximum number of coins of dem=nomination conValue cents that can be obtained from amountLeft cents.
AmountLeft has been decreased by the value of the coins, that is, decreased by number*coinValue.

For example, suppose the value of the variable amountLeft is 86. Then, after the following call, the value of number will be 3 and the value of amountLeft will be 11 (because if you take three quarters from 86 cents, that leaves 11 cents):computeCoins(25, number, amountLeft);

Include a loop that lets the user repeat this computation for new input values untill the user says he or she wants to end the program.
(Hint: Use integer division and the % operator to implement this function.) p>

here is what i have so far i just need to implement this function in this program
void computeCoin(int coinValue, int& number, int& amountLeft);
how do i do that.

#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
void computeCoin(int coinValue, int& number, int& amountLeft); 
// Main Program
int main( )
{


 
// Variable Declations
int coin_value;
int quarters;
int dimes;
int pennies;
int total_amount;
char yes = 'y';
char Yes = 'Y';
char agian;



// Enter code below

do 
{
quarters = 0;
dimes = 0;

pennies = 0;


cout<< " Enter the amount of change ";
cin >> coin_value;
cout << "\n";

if (coin_value >= 25 && coin_value <= 100)
{
quarters = coin_value / 25;
coin_value = coin_value % 25; 
}


if (coin_value <= 24 && coin_value >= 10)
{
dimes = coin_value /10;
coin_value = coin_value % 10; 
}





if (coin_value <= 4 && coin_value >= 1)
{
pennies = coin_value; 
}


////////
total_amount =( quarters * 25)+ (dimes * 10) + pennies;
cout << total_amount << " Cents Can be given as " ;
////////


if (quarters == 1) 
{
cout << quarters << " quarter, ";
}


if (quarters == 2 || quarters == 3)
{
cout << quarters << " quarters, ";
}


if (dimes == 1)
{
cout << dimes << " dime, ";
}


if (dimes == 2 )
{
cout << dimes << " dimes, ";
}




if (pennies == 1) 
{
cout << pennies << " penny. " << endl;
}


if (pennies < 4 && pennies > 2)
{
cout << pennies << " pennies. " << endl;
}


cout << "\n";
cout << " Would you like to run the program agian (Y or N)? ";
cin >> agian;

}


while (agian == yes || agian == Yes);

cout << "\n\nEnd Program.\n";
return 0;
}
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Last Post by restrictment
1

Is it just me, or does this thread look astonishingly similar to this one?:
http://www.daniweb.com/forums/thread261832.html

Please try not to double-thread, as I don't like to read the same thing twice. :(

Also, I posted the formulas that you needed on the other thread. Just integrate them into your current code..but try to understand how the work as well, so you won't be confused on the subject matter later on.

Edited by restrictment: n/a

Votes + Comments
Thanks for pointing it out.
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