/*
say numbers are 2,8,15,51
so upperLimit=51 & lowerLimit=2
*/
int num;
do
num=rand((51-2)+1)+2; //This I deliberately did to denote uLimit & lLimit
while(num!=n1 && num!=n2 && num!=n3 && num!=n4);

rand(x) will always return a number from 0 to (x-1).

hi i would like u to tell me if i can make a random function to choose between four numbers and only them(-1 , 1 , -10 ,10)

Yes, you can. Quite easily, in fact:

int a[] = { -1, 1, -10, 10 };
int choice = a[rand() % 4];

rand(x) will always return a number from 0 to (x-1).

No, rand will always return an integer in the range of [0, RAND_MAX). rand doesn't take any parameters. On top of being overly complicated, your code is flat out wrong. Perhaps you were thinking of one of the many non-portable alternatives (not called rand) that compilers like to offer?

Of course Murhpy's law says that the instant you offer a non-portable solution, people shoot back with "it doesn't work". Then there's the subsequent bout of twenty questions to reach the conclusion that their compiler doesn't support the feature and a standard solution would be better.

That's a real pain, so we just go straight to the standard solution in the first place and avoid the headache.

This is a fingerprint verification application. When verifying,it loops through the table. if the current fingerprint template is the first one on the table row it verifies it correctly. But ...