Hello All,
I'm new here, and glad to be part of this wonderful and helpful site.

I'm trying to allocate a new array (lets say of size 10) inside a struct.
I want to do it this way:

#include <stdlib.h>
#include <stdio.h>

typedef struct Circle {
    int *x;
    int y;
    int r;
} Circle;

typedef struct Circle* CircleP;
typedef struct Circle Circle;

//initialize array of size 10.
CircleP allocateMem() {
    CircleP p=(CircleP) malloc(sizeof(Circle));
    p->x=(int*)malloc(sizeof(int) * 10);
    return p;

int main() {
    Circle circle;
    CircleP circleP=&circle;
    int i;
    int j;
        printf("%d\n", circleP->x[i]);
    return 0;

The program do compile, but when I print the array I get 0 as its values.
What I'm doing wrong?


Recommended Answers

All 4 Replies

Your printing loop counter is j, but you print x.

wow... I can't believe I did that..
Is everything beside that ok? That's how I should allocate memory to an array inside a struct?

Besides checking a return value, allocation is OK. Lines 22-24 look strange though. A simple

CircleP circleP = allocateMem();

is enough.

Thanks nezachem.. I'm new in programming and specially in c.
This Forum is really helpful, many topics helped me a lot for now.

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