hi...
I have a value, value=4501-E001
I am concerned about only the value before hyphen i.e., 4501
I need to check whether various values begin with 4501, followed by something, n am not concerned about "something" that follows.
How can this splitting be done in python?
Jump to PostDon't need to .split('-') but you can check directly begining by startswith.
Jump to Postoctet-string?? Give running code I never heard such a thing? It has not string representation for str function?
if str(value).startswith(start):
Don't need to .split('-') but you can check directly begining by startswith.
Don't need to .split('-') but you can check directly begining by startswith.
thanx for the reply...but the value is an octet string, n when i tried startswith, it said octetstring has no attribute startswith
thanx for the reply...but the value is an octet string, n when i tried startswith, it said octetstring has no attribute startswith
yes...i got a simple solution..
here s it, hoping it might help some newbie like me:)
if value[:4]== '4501':
print "xxx..whatever..."
octet-string?? Give running code I never heard such a thing? It has not string representation for str function?
if str(value).startswith(start):
yes...i got a simple solution..
here s it, hoping it might help some newbie like me:)
if value[:4]== '4501':
print "xxx..whatever..."
What you can do with an object depends entirely on its class. I suspect that your object's class is pyasn1.type.univ.OctetString. You should probably be able to convert the value to a python string by using mystring = str(value) .
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.