0 hiddepolen 32 7 Years Ago Hi Daniweb! I couldnt find my problem anywhere else on this forum, so I decided to make my own thread... My problem: I'm trying to make a function to decide how many decimals a 'double' has. My code (slightly edited, here's the base of it): // int m = 0; int decimal ( double total) { double dec = total - (int) total; if (dec) { m++ dec *=10; decimal (dec); } else return m; } The results: the funtion works, if there're no decimals. Else it returns my max, which is 5. ANY help would be very aprreciated! Thanks in advance c++ decimal double function places

1 Featured Reply MattyRobot 22 7 Years Ago this is an idea I had. remove everything above 0 like you did. then convert the decimal bit to a string. then get the length of the string. #include <iostream> #include <string> #include <sstream> int DecimalPlaces(double test) { double JustDecimals = test - (int) test; std::stringstream converter; converter<< JustDecimals; std::string StringForm(converter.str()); return StringForm.length() - 2 /* -2 characters for the 0. */; } int main() { std::cout<< "decimal places in " << 0.235987 << " " << DecimalPlaces(0.235987); // returns 6 which is right } this works but it does not test exceptions like if the input is not a decimal then dont minus the 2 otherwise DecimalPlaces(3) == -2 oh and the maximum number of decimal places seems to be 6 (with one number to the left of the decimal point). Edited 7 Years Ago by MattyRobot: n/a

0 OPDiscussion Starter hiddepolen 32 7 Years Ago Thanks a lot! I wouldn't have come up with this solution =-) I'll test if this works when I'm home, and mark the thread solved. (The max of 6 decimals doesn't matter, only 5 are needed. )

0 OPDiscussion Starter hiddepolen 32 7 Years Ago Thanks, it works great. Ive put a 'if', so that if there are 0 decimals, it will just return 0. int DecimalPlaces(double test) { double JustDecimals = test - (int) test; if (!JustDecimals) return 0; std::stringstream converter; converter<< JustDecimals; std::string StringForm(converter.str()); return StringForm.length() - 2 /* -2 characters for the 0. */; }