The mod operator is simply the remainder after division. For example, 4%2 is 0 because the remainder after 4/2 is 0. The mod operator works only on integers, not floats or doubles. There is no code to give you because that's all it is -- a simple 5th grade math operation.

Then just use normal division (either float or double). After doing the divion you can call modf() to split the variable into integer and fractional parts. Certainly a lot easier to just use % operator.

int a = 40;
int b = 3;
double intpart = 0;
double result = (double)a/b;
double fract = modf(result,&intpart);
int result = (int)fract*10; // convert 0.3333... to just 3

# include <stdio.h>
int main(){
int a=10,b=3,reminder;
// suppose you want a%b.
reminder = a -(a/b)*b;
printf("\n\n Reminder of %d/%d is %d",a,b,reminder);
return 0;
}

Need some help with this Array. I am trying to get the sum of the even numbers and the sum of the odd numbers using a for each loop. I know the answers to what I am trying to achive are sum of even = 84 and the sum of ...

When I execute this progammatically, I get a table with row heights much larger than when I do this manually.

Note : Sel is the Word.Selection object and the Clipboard contains an Excel Table.

public void AddClipboard()
{
Sel.PasteExcelTable(false,false, false);
var t = Sel.Tables[Sel.Tables.Count];
t.AutoFitBehavior(Word.WdAutoFitBehavior.wdAutoFitContent);
}

I have a 2d matrix with dimension (3, n) called A, I want to calculate the normalization and cross product of two arrays (b,z) (see the code please) for each column (for the first column, then the second one and so on).
the function that I created to find the ...