## Snehamathur

Hello I am new to this community and newbie to c language. I want to code for modulus operator (%) in c.. Need Help.

## hugoguan

% operator is use to divide number, but it output the remainder of the number .exp:4%3=1. 5%3=2.

## Ancient Dragon 5,243

The mod operator is simply the remainder after division. For example, 4%2 is 0 because the remainder after 4/2 is 0. The mod operator works only on integers, not floats or doubles. There is no code to give you because that's all it is -- a simple 5th grade math operation.

And what ^^^ said.[/edit]

## Snehamathur

i know how (%) op works,but i need to calculate reminder without using it.

## Ancient Dragon 5,243

Then just use normal division (either float or double). After doing the divion you can call modf() to split the variable into integer and fractional parts. Certainly a lot easier to just use % operator.

## Snehamathur

Actually, i was asked this question." How would you calculate reminder of two ints without using modulus operator ?"
and i am so confused about it.

## Ancient Dragon 5,243

just like I said

``````int a = 40;
int b = 3;
double intpart = 0;
double result = (double)a/b;
double fract = modf(result,&intpart);
int result = (int)fract*10; // convert 0.3333... to just 3``````

## vinitmittal2008 37

Try this one also..

``````# include <stdio.h>

int main(){
int a=10,b=3,reminder;
// suppose you want a%b.

reminder = a -(a/b)*b;

printf("\n\n  Reminder of %d/%d is %d",a,b,reminder);
return 0;
}``````

This will also work like % operator..

commented: Appriciated +1
commented: nice -- a lot better than mine :) +34

## Snehamathur

Thank You so much, I really appriciate this help, thanks again