confusing!

[salvador01]

hi! i'm beginning to like C, i find it very challenging. and i have this problem, that confuses me here:
Construct a C that will accept 5 digit number, determined the reversed number and display the message "equal" if the original 5 digit number and the reversed number is equal, otherwise display "not equal".

- what confuses me is that how can i determined the reversed number. i have this condition,

input 12345, the reversed number is 54321

Please help me!

[jonsca]

Hint: get the user's input in the form of a char array (use fgets to read the line of text).

[salvador01]

input 12345;
scanf("%c,%c,%c,%c,%c",&n1,&n2,&n3,&n4,&n5);
printf("the reversed number is:%c,%c,%c,%c,%c",n1,n2,n3,n4,n5);

is this what you mean?

[jonsca]

I was thinking more along the lines of the following for input

char number[6];
fgets(number,6,stdin);

Theoretically yours works, but look at the third line and the number is being printed out in the same order. I suppose the comparisons don't take any more work your way.

You'll have to watch that you put in the commas, though, as that's what your scanf is calling for.

[salvador01]

hi! if i get the original number and the reversed number how can make the condition? i have this condition correct me if i have wrong.

if (original number == reversed number)

how can i know if the original and the reversed are equal?
if i have 12345 and the reversed is 54321, how can you determined if they equal or not? by getting the sum of the two numbers or what? please help me

[jonsca]

If you have an array of characters |1|2|3|4|5|\0| you know the third character (at index 2) is always going to be the same, so compare indexes 0 and 4 along with indexes 1 and 3. If the number of matches is equal to 2, they are the same. This may seem more tedious to do, but try using your method on a 1000 digit number.