overloaded function in C++

[AhmedGhazey]

why return type is not a part of function signature
i.e. I can't make such this code

int x (int y){
return 0;
}
float x(int y){
return 0.0;
}

while i can make such this code:

int x (int y){
return 0;
}
int x(String y){
return 0.0;
}

[Narue]

There's too much complexity involved in overloading on return type. It's simply not valuable enough to justify the cost of the feature.

[AhmedGhazey]

because it detect which function should be called from the types of the actual parameters which means a call f(0) and f(0.0) but you dont know f(0) and f(0) if both have different signature (from your point of view that f have an int parameter but different return type) from function call you cant know which one should be called

[AhmedGhazey]

how mark thread as solved