I'm running ubuntu on x86_32...and I keep getting segmentation fault while running this program.
#include<stdio.h>
#include<stddef.h>
char *memcp(char *dest, const char *src, size_t n)
{
char *dp = dest;
const char *sp = src;
while(n--)
*dp++ = *sp++;
return dest;
}
int main()
{
char *s = "abcde";
char *d;
char *r = memcp(d,s,6);
printf("%s",r);
return(0);
}The problem with this code is that it is running on my friend's x86_64 machine on windows as well as ubuntu. Please help me out ..
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main()function you have not allocated memory for the pointerd, In this code you are trying to store values in the unallocated memory which leads to undefined behavior.
In the main() function you have not allocated memory for the pointer d , In this code you are trying to store values in the unallocated memory which leads to undefined behavior.
>>char *r = memcp(d,s,6);
do you mean to call memcpy()? There is rarely a reason to catch the return value of memcmp() because all it returns is the destination buffer pointer. It has no error checking.
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