Hi, its an assignment i need to do. The while loop working on well when i input an integer but when a letter is being input, the while loop run for infinity. I had seen through the other thread but still cannot understand how to do. Please help...
while(choice!=1&&choice!=2&&choice!=3&&choice!=4)
{cout<<"The request is invalid, please try again."<<endl;
cout<<"Please enter your choice again"<<endl;
cin>>choice;
}Jump to PostIf there are less than 10 choices, take in the choice as a character rather than an integer. Check to make sure the character is between '1' and '9' (or '0' and '9' if you want a choice 0).
Alternatively, if a 2+ digit answer is required, take in …
Jump to PostWhat is choice defined as?
If there are less than 10 choices, take in the choice as a character rather than an integer. Check to make sure the character is between '1' and '9' (or '0' and '9' if you want a choice 0).
Alternatively, if a 2+ digit answer is required, take in the input as a string and check each character to see if it's a digit (using the functions in <cctype> if permitted or the approach above if it's not).
What is choice defined as?
the choice is declare as int...
then is normal to fail if you input a character...
define it as char or string
you made the condition as :
while(choice!=1&&choice!=2&&choice!=3&&choice!=4)1 and 2 and 3 and 4 are intergers and the choice is character so you should make it as
while(choice!='1'&&choice!='2'&&choice!='3'&&choice!='4')the choice is declare as int...
choice is character
I said choice should be a character. In the OP's code it is not.
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