So, I'm playing around with SDL and I've come across a bit of a bump. I have one image and I am trying to "free" that image to put on another one. Here is what my code looks like..
// I did get a good section of this code from LazyFoo productions. I have modified it
// I don't take credit for the parts that LazyFoo productions did. :P
int main( int argc, char* args[] )
{
//Make sure the program waits for a quit
bool quit = false;
//Initialize
if( init() == false )
{
return 1;
}
//Load the files
if( load_files() == false )
{
return 1;
}
//Apply the surface to the screen
apply_surface( 0, 0, image, screen );
//Update the screen
if( SDL_Flip( screen ) == -1 )
{
return 1;
}
SDL_Delay (2000);
SDL_FreeSurface( image ); // get rid of the first image
image = load_image("conan.jpg"); // load the second
apply_surface( 0, 0, image, screen ); // apply it to the screen
if( SDL_Flip( screen ) == -1 ) // update screen
{
return 1;
}
// and.. it's ontop of the other image instead of replacing it
SDL_Delay (2000);
//Free the surface and quit SDL
clean_up();
return 0;
}
So, what actually happens is the "conan.jpg" is simply placed over the original image that is loaded in the load_files() function. Just incase my query wasn't clear, what I want to do is get rid of the first image and replace it with a second.
Any help would be appreciated.
Thank you,
- TZ