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/* can any 1 tell me wats the problem."Que: reverse an array without using temporary array " This works for N =5 but when N =6 it displays the original values of an array. */

```
#include <stdio.h>
#include <conio.h>
#define N 6
void print(int b[N])
{
int i;
printf("\n");
for(i=0;i<N;i++)
{
printf("%3d",b[i]);
}
}
void swap(int a[N])
{
int i,j;
for(i=0,j=N-1;i<N,j>=0;i++,j--)
{
if(i!=j)
{//swapping
a[i]=a[i]+a[j];
a[j]=a[i]-a[j];
a[i]=a[i]-a[j];
}
else
{
break;
}
}
}
void read(int b[N])
{
int i;
for(i=0;i<N;i++)
{
printf("\n [%d] : ",i+1);
scanf("%d",&b[i]);
}
}
void main()
{
int a[N],i,j;
clrscr();
read(a);
print(a);
swap(a);
print(a);
getch();
}
```

*Edited
by Narue*: added code tags