Matrix given in memory to print the spiral in opposite direction from clockwise (left column down the right lower range, right up column, a series of upper left, etc. until you get to the middle)
This is matrix
1 2 3
8 9 4
7 6 5
and the result for print is 1 2 3 4 5 6 7 8 9
If anyone could help me???
I have to write code in assembly, but help in c++ would be ok. thanks in advance
include <stdio.h>
#define R 3
#define C 6
void spiralPrint(int m, int n, int a[R][C])
{
int i, k = 0, l = 0;
/* k - starting row index
m - ending row index
l - starting column index
n - ending column index
i - iterator
*/
while (k < m && l < n)
{
/* Print the first row from the remaining rows */
for (i = l; i < n; ++i)
{
printf("%d ", a[k]);
}
k++;
/* Print the last column from the remaining columns */
for (i = k; i < m; ++i)
{
printf("%d ", a[n-1]);
}
n--;
/* Print the last row from the remaining rows */
if ( k < m)
{
for (i = n-1; i >= l; --i)
{
printf("%d ", a[m-1]);
}
m--;
}
/* Print the first column from the remaining columns */
if (l < n)
{
for (i = m-1; i >= k; --i)
{
printf("%d ", a[l]);
}
l++;
}
}
}
/* Driver program to test above functions */
int main()
{
int a[R][C] = { {1, 2, 3, 4, 5, 6},
{7, 8, 9, 10, 11, 12},
{13, 14, 15, 16, 17, 18}
};
spiralPrint(R, C, a);
return 0;
}
If anyone could help me to convert into assembly???? tnx
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