``````#include<stdio.h>

main()
{
int array[100], n, c, d, swap;

printf("Enter number of elements\n");
scanf("%d", &n);

printf("Enter %d integers\n", n);

for ( c = 0 ; c < n ; c++ )
scanf("%d", &array[c]);

for ( c = 0 ; c < ( n - 1 ) ; c++ )
{
for ( d = 0 ; d < n - c - 1 ; d++ )
{
if ( array[d] > array[d+1] ) /* For decreasing order use < */
{
swap = array[d];
array[d] = array[d+1];
array[d+1] = swap;
}
}
}

printf("Sorted list in ascending order:\n");

for ( c = 0 ; c < n ; c++ )
printf("%d\n", array[c]);

return 0;
}``````

my doubt is in this sorting algorithm everything is stored in the array[c] but why they use array[d] can u explain me???

Uh, learn how variables work.

`````` for ( c = 0 ; c < n ; c++ )
scanf("%d", &array[c]);
``````

in the beggining c=0 , therefore when reading an integer into array[c] it actually
means you read an integer into the 0 place ( aka array[0] )

after placing a number …

## All 5 Replies

Uh, learn how variables work.

but they did not assign array[c]=array[d]

c and d are just the index of array..

interprete the programme put values of c and d you will undersatnd
And array[c] or array[d] are not diffrent but same variable.
just index changes like array[0],array[1].....

`````` for ( c = 0 ; c < n ; c++ )
scanf("%d", &array[c]);
``````

in the beggining c=0 , therefore when reading an integer into array[c] it actually
means you read an integer into the 0 place ( aka array[0] )

after placing a number in the array[0] place, 'c' grows by one (`for(....;c++)`
and the next number goes into the next array place.

think of c and d as place markers
if you do

``````int c=0;
int d=0;

if (array[c]==array[d])
puts("of course they are its like saying array[0]==array[0]");
else
puts("not sure i'll open the c book and try to figure it out");

puts("thanks anyway");
``````

what output will you get? good luck :O

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