public class NewClass {
    public static void main(String[] args){
    int[] a=null;
    int p=0;
    int i=0;
    while(p<11){
    a[i]=p;
    p++;
    i++;
    }
    }
}

what is wrong here.....here the array can not store data.

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In java u have to dynamically alocate resources for array...
for Line 3 you need
a = new int[size of array];

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while(p<11){

a better approach would be to change the above to:

while (p < a.length)

since you don't always know the length up front. this way, you won't reach an arrayIndexOutOfBoundsException, whether you keep the same number of elements or decide to …

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In java u have to dynamically alocate resources for array...
for Line 3 you need
a = new int[size of array];

@Onlineshade ,
It wil lshow null pointer exception at line 7,
because of line 3,

 // declares an array of integers
    int[] anArray;

    // allocates memory for 10 integers
    anArray = new int[10];
/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */

/**
 *
 * 
 */
public class NewClass {
    public static void main(String[] args){
    int[] a;
    a=new int[10];
    int p=0;
    int i=0;
    while(p<11){
    a[i]=p;
    p++;
    i++;
    }
    }
}



Still some problems....oh!
**Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 10
   at NewClass.main(NewClass.java:17)
  Java Result: 1
 BUILD SUCCESSFUL (total time: 0 seconds)**

The ArrayIndexOutOfBounds is happening due to the while loop.
while (p<11)
this executes 0-10.
However our range is from 0-9. (Because we have an array of 10 integers)

change while (p<10) and I guess your code should work fine :)

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You have to declare the size of an array before you can put and retrieve data from it.. Otherwise it will create an error..

while(p<11){

a better approach would be to change the above to:

while (p < a.length)

since you don't always know the length up front. this way, you won't reach an arrayIndexOutOfBoundsException, whether you keep the same number of elements or decide to change that number.

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