i am unable to understand the code. can anyone please explain.

printf("%d",i & 1)
wat is the &1??

int i;
for(i=0;i<10;++i)
printf("%d",i &1);

Edited 4 Years Ago by Dani: Not a code snippet

well, i saw your given link... much of the content just bounced off my head.. can u please expain me in simple terms...

Ok, so...
AND truth table

This is the table
0 & 0 = 0
1 & 0 = 0
0 & 1 = 0
1 & 1 = 1

This is the truth table of the AND bitwise operator. In programming language every single thing is transalted into bytes, and smaller bits.
1 byte=8 bits.
Here are some info about bits: http://en.wikipedia.org/wiki/Bit
So, in your case you had a for from 0 to 9, all of that bitwise and with 1 (i & 1).
First of all we will translate every single i into binary:

Decimal     Bianry
0           0000
1           0001
2           0010
3           0011
4           0100
5           0101
6           0110
7           0111
8           1000
9           1001

Ok so, we have the numbers into binary, and we have the AND bitwise table.
We now have to bitwise and them together.
so we start with 0 & 1:

We have 0 & 1:

0 0 0 0 &
0 0 0 1
-------
0 0 0 0

//You take from the table every single digit.
//So first: it's from right to left: 0 with 1 from the table is 0, then 0 & 0 is zero. So the
//answer is 0 0 0 0.

We have 1 & 1:

0 0 0 1 &
0 0 0 1
-------
0 0 0 1

//0001 in binary if you check the table is 1, so the answer is 1.

We take 2 & 1:

0 0 1 0 &
0 0 0 1
-------
0 0 0 0

//0000 in binary is 0.
//don't forget, you have to check every single pair digit, so 0 & 1 is 0, 1 & 0 is 0 etc.

And you do that with every single number.

Hope I made myself clear:D

For example, if you bitwise & 6 with 13 it will give you 4:

6:      0110
13:     1100

0 1 1 0 &
1 1 0 0
-------
0 1 0 0
//which is 4 from the conversion table.

Edited 4 Years Ago by Lucaci Andrew

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