#include <stdio.h>
#include <stdlib.h>

void main()
{
char x[10],y[10];
int i,j,k,flag=0;
printf("enter the string: ");
fgets(x,sizof(x),stdin);
for(i=0;x[i]!='\0';i++)
for(j=0,k=i;x[k]!='\0';j++,k--)
{
    y[j]=x[k];
    }
    if(x==y)
    {
        printf("the string is palindrome");
    }
    else
    {
        printf("not palindrome");
    }
}

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This could easily be solved with the strrev function from the string library
here's a link with the answer

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try to check the beginning and end of the indeces of the string if equal. The index starting from the beginning to increment and the index starting at the end to decrement and comparing both of them
e.g.

       //here int i is the counter of the …
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what now ?

error at line 9

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it is sizeof() operator, not sizof. spelling error. check it now.

This could easily be solved with the strrev function from the string library
here's a link with the answer

but my target is without using any string functions myfriend

try to check the beginning and end of the indeces of the string if equal. The index starting from the beginning to increment and the index starting at the end to decrement and comparing both of them
e.g.

       //here int i is the counter of the index from the start of the word and j from the end and n as the counter to check if the word is a palindrome
       j = strlen(string) - 1;
       for(i = 0; i <= j ; i++,j--){                   
           if(string[i]!=string[j]){                
               n=1; //counter tells that the sting is currently not a palindrome                                 
               break;  //once found that character doesn't matches it breaks from the loop                             
           }
           if(string[i]==string[j]){                
               n=0; //counter tells that the sting is currently a palindrome                                
           } 
       } 

then print the word is not a palindrome if the value of n is 1 else a palindrome

ooh i didnt think at all any way thanks zeroliken

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