error C2660: 'std::vector<_Ty>::empty' :

[Lp_baez]

I keep getting this error on a sample that a c++ book provides.

"

 **error C2660: 'std::vector<_Ty>::empty' : function does not take 1 arguments
    1>          with
    1>          [
    1>              _Ty=std::string
    1> **         ]

"
I have some suspicious what can be causing the error but I am not sure.
the code is:

#include <iostream>
#include <string>
#include <vector>

using namespace std;

int main()
{
    vector<string> inventory;
    inventory.push_back("sword");
    inventory.push_back("armor");
    inventory.push_back("shield");

    cout << "You have " << inventory.size() << " items.\n";
    cout << "\nYour items:\n";
    for (unsigned int i = 0; i < inventory.size(); ++i)
    {
        cout << inventory[i] << endl;
    }

    cout << "\nYou trade your sword for a battle axe.";
    inventory[0] = "battle axe";
    cout << "\nYour items:\n";
    for (unsigned int i = 0; i < inventory.size(); ++i)
    {
        cout << inventory[i] << endl;
    }

    cout << "\nThe item name '" << inventory[0] << "' has ";
    cout << inventory[0].size() << " letters in it.\n";

    cout << "\nYour shield is destroyed in a fierce battle.";
    inventory.pop_back();
    cout << "\nYour items:\n";
    for (unsigned int i = 0; i < inventory.size(); ++i)
    {
        cout << inventory[i] << endl;
    }

    cout << "\nYou were robbed of all of your possessions by a thief.";
    inventory.clear();
    if (inventory.empty())
    {
        cout << "\nYou have nothing.\n";
    }
    else
    {
        cout << "\nYou have at least one item.\n";
    }

    return 0;
}

[Moschops]

That code compiles without any problems. This suggests that the code you showed us is not the code you're trying to compile.

[Unimportant]

Hey, the error is

vector.empty() doesn't take 1 argument