Hi guys i am new here
i want to help about:
how to convert digit(number) into word
for example:
Enter a number:123
Output:one two three

Re: help 80 80

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Re: help 80 80

Start by working out the logic in ordinary English forget the Java for now.
Write down a few numbers, work out the correct answers, write doen how you did that. Then translate that into Java.

Re: help 80 80

this program
solve by array or for loops

Re: help 80 80

String a[] = {"Zero","One", "Two", "Three", "Four", "Five", "Six" , "Seven","Eight","Nine"};

Re: help 80 80

That's a good start. Given the irregular pattern for the teens it nay be worth carrying on with that up to 19

Re: help 80 80

and, depending on how far it must go, add logic for thousands and hundreds.
it's not at all difficut to implement, if you just want:
213
to be translated into
two one three
you can just print the elements of the array you already have by using the numbers-to-translate as indices.
if you need to go for more correct numbers, you'll have to add some conditional statements and different arrays, but it isn't much more difficult.

Re: help 80 80

this program without hundred and thousand jusd red simple numbers . and this program too much difficult .also i try alot to solve ..
please help me .

Re: help 80 80
import java.util.*;
class word_num
 {
  public static void main (String [] args)
    {
     int x,i;
     String m="\t";
     System.outprintln("Enter number");
     Scanner ip =new Scanner(System.in);
     for (i=1; i<=3; i++)
        {
        x=ip.nextIn();
        if(x==1)
        m=m+"one\t";
        else if (x==0)
        m=m+"zero\t";
        else if (x==2)
        m=m+"two\t";
        else if (x==3)
        m=m+"three\t";
        else if (x==4)
        m=m+"four\t";
        else if (x==5)
        m=m+"five\t";
        else if (x==6)
        m=m+"six\t";
        else if (x==7)
        m=m+"seven\t";
        else if (x==8)
        m=m+"eight\t";
        else if (x==9)
        m=m+"nine\t";
        }

        System.out.println("\n"+m);
     }
   }
Re: help 80 80

ehm .. if you don't need to take into account hundreds/thousands, I 've told you in my previous reply how to solve it, using the array you have, and with a lot less code than this.

don't ignore answers, go through them and ask about them if you don't understand them.

Re: help 80 80

thanks for answer
I am realy dont know how to use array in this program

Re: help 80 80
import java.util.*;
class word_num
 {
  public static void main (String[] args)
    {
     int k,rev,k1;
     int b;
     Scanner sc=new Scanner(System.in);
     System.out.println("Enter any integer Numbers");
     k=sc.nextInt();
     k1=k;
     while(k!=0)
     {
     b=k%10; 
     rev=rev*10+b;
     k=k/10;
     }
     b=rev%10;
     switch(b)
     {
     case 0:
     System.out.println("zero"); break;
     case 1:
     System.out.println("one"); break;
     case 2:
     System.out.println("two"); break;
     case 3:
     System.out.println("three"); break;
     case 4:
     System.out.println("four"); break;
     case 5:
     System.out.println("five"); break;
     case 6:
     System.out.println("six"); break;
     case 7:
     System.out.println("seven"); break;
     case 8:
     System.out.println("eight"); break;
     case 9:
     System.out.println("nine"); break;
     }
     rev=rev/10;
     }
     }
Re: help 80 80

The switch is OK, but the array was better. Here's how it works:
If you have your array as before

String a[] = {"Zero","One", "Two", "Three", "Four", "Five", "Six" , "Seven","Eight","Nine"};

Then
a[0] is "Zero"
a[1] is "One"
etc.
so if you have an int b with values 0-9 then a[b] is the corresponding string.

Re: help 80 80

how I can int b with values 0-9 (i use array)

Re: help 80 80

You already have it. That's exactly the same "b" that you use for your switch!

Re: help 80 80

thanks
i understand this point ^^

Re: help 80 80

i try this program

import java.util.*;
class word_num
 {
  public static void main (String[] args)
    {
     int b; 
     String a[] = {"Zero","One", "Two", "Three", "Four", "Five", "Six" , "Seven","Eight","Nine"};
     Scanner sc=new Scanner(System.in);
     System.out.println("Enter any integer Numbers");
     b=sc.nextInt();
     System.out.println(a[b]);

    } 
}

it is work , but it read just one number not more
like 7 7 seven
83 eight

Re: help 80 80

In your previous (switch) program you had a loop that was doing /10 and %10 calculations to get each of the digits in turn. You still need a loop with something like that to get each of the digits.

Re: help 80 80

like this

for(b=1; b<=10; b++)
     {
     b=b/10;
     b=b%10;
     }
Re: help 80 80

like this

for(b=1; b<=10; b++)
     {
     b=b/10;
     b=b%10;
     }
Re: help 80 80

No. Go back and look at your pervious code - I didn't read it all but it looks like it was doing the right kind of stuff

(ps - its dinner time here in France, I'm offline until tomorrow. Good luck. J)

Re: help 80 80

thanks for all answers
have nice dinner ^_^

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