You are required to write a C++ program to covert a positive inter code into English name equivalent for the digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in a code.

If input is 234056 the output is: IVALID CODE(Presence of zero)
If input is 23456 the output is: TWO THREE FOUR FIVE SIX
If input is9349 the e output is: NINE THREE FOUR NINE
If input is245 the output is: INVALID CODE(3 DIGITS)
If input is 2344567 the output is: INVALID CODE (7 DIGITS)

Steps to follow to write the program as follow:

Step1 Input cod

Step2 Count the number of digits in the code

Step3 If there is a zeroin the code, “Invalid Code(presence of zero)”else GOTO step4

Step4 If number of digits is mode of equal than 4 and less or equal than 6, GO TO step 5 else display the following message “INVALID CODE (<number of digits>DIGITS)

Step5 Call function called digit_name tocovert each digit into its equivalent English name.
Display the result

Step6 Print the digits in reverse order.Eg; if input is 13453, reverse order is 35431

Overall valid output: (example)
Input in 12345
Reverse order of code: 54321

Important:Use array. Loops and function appropriately

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I still dont take this subject but I want to know how to do it >> coz I saw defferent answers in google
ex >> they put function like ( cout , cin )
I thought we can use (printf , scanf )

my friends told me " you will take c++ in next semester "
thats why I want to know it

That doesn't make it any less of a homework assignment according to our rules.