0

Ok, i have this program

It determines if the number entered is a prime or not.

I did that, posted it, and now i need to do this:

Determine and print the prime numbers between a user-specified lower bound and user-specified upper bound.

Read all through my text and browsed all over the net... How exactly would you do that? Is there a certain function?

This isnt homework, well, its extra credit while over break.

```
#include <cstdlib>
#include <iostream>
#include <iomanip>
#include <stdlib.h>
using namespace std;
const unsigned W = 10;
int main(int argc, char *argv[])
{
const unsigned long arraySize = 1000000;
bool a[arraySize];
unsigned long b, x;
unsigned long counter = 0;
unsigned long primes = 0;
char z;
cout<<"This program is programming assignemnt #5."<<endl;
cout<<"THE SIEVE OF ERATOSTHENES."<<endl;
cout<<"By Jeremy Rice of CSCI 111."<<endl;
//Initializing elements to 1
for (int i = 0; i < arraySize; i++)
{
a[i] = 1;
}
// For array subscript 2, all elements beyond 2 in the array that
// are multiples of 2 will be set to zero ; for array subscript 3,
// all elements beyond 3 in the array that
// are multiples of 3 will be set to zero
for (int i = 2; i * i < arraySize; i++)
if (a[i])
for (int j = i + i; j < arraySize; j += i)
a[j] = 0;
// print all subscripts set to 1
do
{
cout<<"Prime > ";
cin>>b;
if (a[b] == 1)
{
cout<<b<<" is a prime number."<<endl;
}
else if
(a[b] == 0)
cout<<"This is not a prime number."<<endl;
cout<<"Check another number? (Y/N)"<<endl;
cin>>z;
} while((z == 'y')||(z == 'Y'));
system("pause");
return 0;
}
```