C++ program that determines direction of sorting and reversing it

[Ahmed_217]

I need a c++ program that is able to determine whether or not a given array is sorted in ascending or descending order. then after that the program should reverse the direction of order

[rproffitt]

How much is being paid for this app?

[Reverend Jim]

Ditto rproffitt, but have you considered there is a possible third state? What if the array is not sorted at all? What happens then? If you are guaranteed that it is sorted then you only have to check the first two elements, or the first and last to determine the direction, assuming the items are unique. If the number of elements is one or zero then the problem becomes trivial.

But you'll still need to implement a sort.

[toneewa]

This should do what you asked.

#include <iostream>
using namespace std;

int main()
{
    int n, i, arr[50], flag = 0;
    cout << "Enter the size of array: ";
    cin >> n;
    cout << "Enter the elements of array: ";
    for (i = 0; i < n; i++)
        cin >> arr[i];
    for (i = 1; i < n; i++)
    {
        if (arr[i] > arr[i - 1])
        {
            flag = 1;
            break;
        }
    }
    if (flag == 0)
        cout << "The array is sorted in descending order." << endl;
    else
    {
        flag = 0;
        for (i = 1; i < n; i++)
        {
            if (arr[i] < arr[i - 1])
            {
                flag = 1;
                break;
            }
        }
        if (flag == 0)
            cout << "The array is sorted in ascending order." << endl;
        else
            cout << "The array is not sorted." << endl;
    }
    cout << "The reversed array is: ";
    for (i = n - 1; i >= 0; i--)
        cout << arr[i] << " ";
    return 0;
}

Enter the size of array: 5
Enter the elements of array: 5
4
3
2
1
The array is sorted in descending order.
The reversed array is: 1 2 3 4 5