Hi Guys, Im currantly having a problem with simulating balls bouncing of each other in a 2d space, everything is working and all, but it just doesant seem natural for me... If we had any math wizzes here now is your time please:) my circles are painted inside of rectangles..... This is what is the code im using to find the new x and y coordinates of the circles. specifically this piece here... //Pythagerum theorem, a^2 + b^2 = c^2, to figure out the distance between the two circles' centers. int distance = (int) Math.sqrt(((currantXa - currantXb) * (currantXa - … +0 Hello! I am looking for some help, and have provided the code. I'm just trying to do some simple stuff. I'm trying to create a simple game without using classes (but using lists). What I'm trying to do is create collision detection among list objects ("bullets" and "baddies"), as you'll be able to see in the code. I'm also trying to fire 10 bullets at once from an "ammoCrate". My problem is that I have to stay on the "ammoCrate" in order for the bullets to do their thing, otherwise they stop in place and disappear, but continue if the … +0 Tutorial Keep it Hot! The secret to high-performance code This tutorial is the first time I write about coding techniques for improving the performance of software. This is going to be a step-by-step journey through a real example, with real benchmark results at every step so that you can see the effect of the different optimization techniques. And as my first tutorial on performance optimization, I have to talk about the most important principle in performance optimization: keeping things hot. If you expect this tutorial to be about showing bits of code and the assembly listings generated by the compiler and then, showing how to reduce the number of … +7 Hey, all! I'm trying to figure out how to add collision detection to the following code but I'm having trouble trying to figure out how to pull in the x and y coordinates of the different eggs that are falling randomly. Would you be able to tell me what I'm doing wrong? Thank you!

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