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pow 14 Years Ago by maryam ahmad … 2008\projects\inv2\inv2\inv2.cpp(145) : error C2668: 'pow' : ambiguous call to overloaded function 1> c:\program files…\vc\include\math.h(575): could be 'long double pow(long double,int)' 1> c:\program files\microsoft … 9.0\vc\include\math.h(527): or 'float pow(float,int)' 1> c:\program files\microsoft visual … Re: pow 14 Years Ago by Fbody …makes the difference because there is no definition of pow() for pow(int,int). Since an int can be automatically …k, I would suggest a cast when you call pow(). If you cast the second argument, you explicitly request… a specific overloaded version. [CODE] pow( neg1, (double)i+k) [/CODE] [edit] nvm. I… Re: pow 14 Years Ago by NP-complete … take jonsca's advice and make the call to pow as [code]pow(-1.0,i+k)[/code]. It just gives you… errors are definitely not due to a wrong call to pow. Or so I guess. BTW, even I compiled it using… Re: pow 14 Years Ago by Sky Diploma Its probably finding the first argument ambigious as the compiler is considering -1 to be an integer. maybe try, [code] long double neg1=-1; cout<< pow(neg1,i+k); [/code] However i'm not sure whether this would work. pow() ?? 20 Years Ago by wal99d …;,op2); printf("====\n"); printf("%d\n",pow(op1,op2)); /* the output is for sure 2 */ } [/code][/B… Re: pow() ?? 20 Years Ago by Dave Sinkula …;====\n"); printf("%[COLOR=Blue]g[/COLOR]\n",pow(op1,op2)); /* the output is for sure 2 */[/code… Re: pow(a, b) fails compiler 17 Years Ago by sgw …QUOTE=vijayan121;530307]your compiler may require [ICODE] c = std::pow( a, b ) ;[/ICODE]. this is correct as you … an ambiguous call to overloaded function. [ICODE] c = std::pow( double(a), b ) ;[/ICODE]. should remove the ambiguity.[/QUOTE…why doesn't the following work: [ICODE] c = std::pow( [COLOR="Green"]int[/COLOR](a), [COLOR="… Re: pow(a, b) fails compiler 17 Years Ago by sgw … and it says "call of overloaded pow(int, int) is ambiguous. Candidates are: double std…::pow(double, double) float std::pow(float, float) long double std::pow(long double, long double)… double std::pow(double, int) float std::pow(float, int) long double std::pow(long double, int)"… Re: pow(a, b) fails compiler 17 Years Ago by vijayan121 … more likely reason is that the function pow is overloaded in c++ [code]double pow ( double base, double exponent ); long… base, long double exponent ); float pow ( float base, float exponent );[/code] and pow(a,b) results in an ambiguous …call to overloaded function. [ICODE] c = std::pow( double(a), b ) ;[/ICODE]. should remove the ambiguity. Re: pow(a, b) fails compiler 17 Years Ago by vijayan121 … are: [CODE]float std::pow( float, float ) ; float std::pow ( float, int ) ; double std::pow( double, double ) ; double std::pow( double, int ) ; long double… std::pow( long double, long double… pow: DOMAIN error 20 Years Ago by ellisrn … mu[i][j] = A[i][j] + B[i][j] * pow(10, (C[i][j]*t)); } } for(i=1; i …<= q; r++) { sum_part[i][q] += comb(q,r) * pow(benij[i][j], r) * yt[j][q-r]; } } } }… pow(double, double) question 15 Years Ago by joshjgordon I am trying to use pow in c++ and for some daft reason it is not … double exponent = 1.5; f.push_back( - ( q * oq ) *d / abs(pow(screen, (double)exponent))); [/CODE] where q, oq and d are… set elsewhere. when I run this it calculates pow(double, int), instead of pow(double, double) as expected. Cheers for any help… pow(a, b) fails compiler 17 Years Ago by sgw Hi, I'm trying to use the pow function. Extremely simple program like the following, but it never …, c; a=2; b=3; [COLOR="Red"]c=pow(a, b);[/COLOR] cout << c; return 0; } Compiler…?:icon_rolleyes: Thanks in advance. (even fails with just "c=pow(2, 3)") Pow Error? Where? 16 Years Ago by gretty … code but I am getting an error with the "pow" function & I have no idea what is wrong…) { int n2, co; while ((n2 != 1) || (n2 != 4)) { co++; n2 = pow(n1,2); // this is where I get my error "…;call of overloaded pow is ambiguous" ???? } cout << n1 << "… Re: pow: DOMAIN error 20 Years Ago by Dave Sinkula …][font=Times New Roman]The [/font][b][font=Courier-Bold]pow [/b][/font][font=Times New Roman]functions compute [/font][b… Re: Pow Error? Where? 16 Years Ago by stephen84s … by 10 gives a zero. As far as your "pow()" call is concerned, the last time I used C…++ and specially "pow()" in that, I recollect it needed the base to… Re: Pow Error? Where? 16 Years Ago by gretty … =0; n3 != 1 || n3 != 4; i++) { co++; n3 = ( pow((double)tens,2) + pow((double)ones,2)); cout << "n3 = "… Re: pow(a, b) fails compiler 17 Years Ago by WaltP It depends on what the 'fail' is. I assume it's because (this is a fact not an assumption) the parameters for the [icode]pow()[/icode] function are not integers. But I might be wrong that that's what your 'failure' is. Re: pow(a, b) fails compiler 17 Years Ago by sgw … a fact not an assumption) the parameters for the [icode]pow()[/icode] function are not integers. But I might be wrong… Pow Function 17 Years Ago by Traicey …... have got this question paper and there is something about pow function... when I asked my instructor about it, he just… it out....well now back to my concern...what is pow function, how does it work, when and where do u… Re: Pow Function 17 Years Ago by leverin4 The following code is a very simple program using the pow function. It is in the cmath library, so you need … <cmath> int main() { int num = 4, cube; cube = pow (num, 3); cout << "The cube of "… Re: pow( ) Having trouble with y = 1 - x ^ 4 14 Years Ago by coil Great! The method Math.pow(x, y) raises x to the power of y. So when you did pow(1-x, 4), you raised (1-x) to the power of 4. However, 1-pow(x, 4) raises x to the power of 4, then it subtracts it from 1. Hope that makes sense Re: pow( ) Having trouble with y = 1 - x ^ 4 14 Years Ago by DeIntegro … x to the power of y. So when you did pow(1-x, 4), you raised (1-x) to the power… of 4. However, 1-pow(x, 4) raises x to the power of 4, then… Re: Pow Function 17 Years Ago by White-Gandalf [url]http://www.google.com/search?hl=en&q=cpp+math+pow&btnG=Search[/url] [url]http://en.wikipedia.org/wiki/Power[/url] -> [url]http://en.wikipedia.org/wiki/Exponentiation[/url] Re: pow( ) Having trouble with y = 1 - x ^ 4 14 Years Ago by coil [icode]float y = pow(1-n, 4); [/icode] actually represents (1-x)^4. I assume that's not what you want. If you want 1-(x^4), do this: [icode]float y=1-pow(n, 4)[/icode] Re: pow( ) Having trouble with y = 1 - x ^ 4 14 Years Ago by DeIntegro [QUOTE=coil;1314849][icode]float y = pow(1-n, 4); [/icode] actually represents (1-x)^4. I … want 1-(x^4), do this: [icode]float y=1-pow(n, 4)[/icode][/QUOTE] Thanks it worked! but i don… Re: pow function for variables 14 Years Ago by NathanOliver use the pow function. [code=c++] foo = pow(bar, 3); [/code] Re: Pow function 12 Years Ago by deceptikon …'ve been given an assignment to write a floating point pow() without any math.h functions in the first few weeks….c). They're designed to be short and simple, yet pow() still depends on a relatively large amount of scaffolding. pow(8,1/3);? 16 Years Ago by rudasi Hi, I have been trying to figure this out and I know it must be something simple but I cant get it. Why does the following code give an answer of 1. double a=8; cout<<pow(a,1/3); I would think it should be 2. Thanks pow( ) Having trouble with y = 1 - x ^ 4 14 Years Ago by DeIntegro I understand that y = n ^ 4 will be pow(n,4)...but what about drawing the curve y = 1 - x ^ 4 y = (1 - x) ^ 4 y = 1-(1 - x) ^ 4 I appreciate your help. Thanks.