#include <stdio.h>
#include <math.h>

int main()
	double op1,op2;
	char opp;
	char *res= "2 ^ 1";

	sscanf(res,"%d %c %d",&op1,&opp,&op2);

	printf("%d\n",pow(op1,op2)); /* the output is for sure 2 */

but it output :
1073741824 <-- ??? I don't know what here so please any helping will be appreciated thankx


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For doubles, use specifiers for doubles, not ints.

sscanf(res,"%lf %c %lf",&op1,&opp,&op2);

	printf("%g\n",pow(op1,op2)); /* the output is for sure 2 */

thankx Dave :p

Davedo you have a simple code that can read a file let's say "xx.txt" line by line? :rolleyes:

Thankx Dave ,but my question is the "%g" means what ?


g      The double argument is converted in style  f  or  e
              (or  E for G conversions).  The precision specifies
              the number of significant digits.  If the precision
              is missing, 6 digits are given; if the precision is
              zero, it is treated as 1.  Style e is used  if  the
              exponent  from  its  conversion  is less than -4 or
              greater than or equal to the  precision.   Trailing
              zeros  are  removed from the fractional part of the
              result; a decimal point appears only if it is  fol-
              lowed by at least one digit.
fputs ( line, stdout ); /* write the line */

I want to save the passed lines into an array
for example:
char *res;

Go with C++ and use a vector of strings. Maybe something similar to this.

#include <iostream>
#include <fstream>
#include <string>
#include <vector>
using namespace std;

int main()
   static const char filename[] = __FILE__;
   ifstream file(filename);
   string line;
   vector<string> text;
   while ( getline(file, line) )
   for ( vector<string>::size_type i = 0, size = text.size(); i < size; ++i )
      cout << text[i] << endl;
   return 0;

Thankx Dave ;)

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