Posts by radhakrishna.p

have you tested your code(after adding sqljdbc.jar to your project build path)?

and let me know the status

hai joseph.lyons,

you need to take the input value for pub name to search from either of the one mechanism

by using this way-1

 String pubName = JOptionPane.showInputDialog("Please Enter the pubs name you wish to search.");
 // this mechanism expects value for pubname from its input box

or using this way-2

String pubName = sc.next();    // this mechanism expects input value for pub name from the command prompt

i think this might be the one reason:

when you came after the vale given into the JoptionPane.ShowInputDialog() method your programs is waiting for the user input which takes from command prompt until you enter the value (i mean this sc.next() makes your program like that)

but you did not do that i think.

thats the reason your program was stopped there without executing the remaining statements

please use one of the above ways for getting input from the user

and make changes to your program accordingly the ways what i described above

i think you will get my point

let me know if you have any doubts in my calrification as well as the status after the modification of your program

any comments are appreciated
[modified]

could you please mark this thread as solved if you got your answer

thanks

hai Shania_01,

you can also connect ms access database by creating Data Source Name For your access file otherwise you need to add ms access connector related jar file to your application as stultuske said

you may try the following urls, it helps you a lot

http://www.hossainkhan.info/content/using-ms-access-java-through-jdbc-odbc-connection

this URL is for different ways of connecting ms access database from java application

http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=2691&lngWId=2

hai silvercats,

instead of onblur() use onkeyup() or onkeypress() for this requirement

check it once by adding any of the actions to the feild

let me know the status

happy coding

hai Naruse,

the following URL may helps you

http://msdn.microsoft.com/en-us/library/system.drawing.bitmap.getpixel.aspx?cs-save-lang=1&cs-lang=vb#code-snippet-1

let me know the status

happy coding

hai darylglenng and to all,

along with the modifications which are specified in above posts

please also do the following things:

1. remove or comment <!-- this at line no 18

2.at line no 39 and 44 you missed the '(' for if condition

it should be like

if(course.value =="")
{
     // your code 
}
if(year.value =="")
{
// your code 
}

and also you stylesheet code would be like as follows

<style type="text/css">  

.style1{
     font-family: Arial, Helvetica, sans-serif;
     color: #00000000;
}

</style>

your form tag should be like as

<form action="" method="POST" name="TheForm" class="style1" onsubmit="JavaScript: return(validate());">

check it once by changing the code as desribed above

let me know the status

happy coding
[Modified]

hai turpentyne,

i am getting confusion about your requirement

can you clearly explain me about the requirement?

If I clicked 'name_2', (this), i need to set a variable from 'name_b', within it

so that i will try to give a way to solution

happy coding

hai shipley,

mysql update query not working

what does it mean (how can we understand by posting a problem like that) ?

colud you please explain me clearly whats the problem you got?

hai kert,

in the given url (a new problem),

i have seen nothing in test.js except alert('your book is overdue') but you are asking something related to that test.js related code.

could please explain me clearly about the problem or Show me an image of that problem?

so that we will try to give you a way to solution

happy coding

hai milkman93

as somjit{} said along with that, you may use static block concept for your requirement like as follows

class SampleTest
{
  static{
       ArrayList<String> arr = new ArrayList<String>()
       arr.add("A"); 
       arr.add("B"); 
       // code for printing these array list values values
  }
}

and these static blocks are executed while class is loading without creating object

let me know if you have any dioubts in my clarification

hai jmw5598,

i am not much aware of Connector J but
i forgot to tell one more thing

you need to add/copy/include the mysql related jar file to your project libraries that jar file you can find in your database installation folder

i mean YOUR_DB_instalation_folder/lib/ (please check there you can find it there)

please try to do like that

and let me know the status

haooy coding

hai chdboy,
please do as follows

Right click on Your Project
    ->then click on BuildPath
      -> then go to Libraries
       ->then click on Addexternaljar  
       and then click ok 

thats it

hai chdboy,

please add/include sqljdbc.jar file to your project build path

check it once after adding the jar file to your project

let me know the status

hai jmw5598,

i think you have not loaded the mysql related driver in order to provide communication between your application and databse

for this , add this line before at line 20 in your ConnectionManager class

Class.forName("com.mysql.jdbc.Driver");

then everything goes fine

please refer this url it explains everything

http://www.vogella.com/articles/MySQLJava/article.html

check it once and let me know

please mark this thread as solved if you got your answer

hai subratbehera,

i think you need to store inwardBean in any of the scope(like request or session) in PagingCIFAction
before forwarding the request to display the values of it.

so that the values will be available for the page where you want to display

try to place this line at line 10 in PagingCIFAction

request.setAttribute("inwardBean",bean); // like this

check it once and let me know

in addtion to the above post:

try to do as follows

place this call $("#candidatetable").tablesorter(); inside the bellow function in your script code

$("#showTable").click(function(event){    
     // your code here 
    $("#candidatetable").tablesorter();
}

check it once and let me know the status

any comments are appreciated

hai Kert

what i guessed is

in your dynamic version page, you have to call the bellow method

$("#candidatetable").tablesorter(); 

the time after loading the results in table, not on the page load (what i mean is while loading the page there is no content in the table)

i think you got the point

check it once and let me know if you have any doubts in my clarification

happy coding

hai Lamirp

your code works fine for the first time.

when you call that method makeCheckBox(Jobs object) for second time it throws an error to you
because you are creating the Jcheckbox with the same reference of the Jcheckbox what you created for first time

so i think you need to change your code

let me know am i correct or not

happy coding

hai gyno,

you dont have to download any plugins seperately for activating those two servers.
those will be installed with netbeans installation process but you need to select those servers at the time installation process starts........

netbeans installer will take care of installing these 2 servers in your system

come to the point for activating servers:

it depend on the application what you want to create.

for example if you want to create java web application

while creating a new web application it will ask for server type apache tomcat or glassfih

then while runnning the application the underlying server will be activated

let me know if you have any doubts in my clarification

please go through the following url: it explains everything what i said above

http://netbeans.org/kb/docs/web/mysql-webapp.html

thats it,
[modified]

hai Yarra,

could you tell me how you initialize the values for these bgReady,heroReady,monsterReady variables in your script?

based on the values of these variables you could not run the render() method directly i think (what i mean is if the values of all these variables are 'false' then the function not works)

and also you have forgotten to give the code relating to these variables

it will be easy for us if we look at that code (post that code also)

happy coding

i saw just you missed the echo keyword for displaying the value

but you got it

thats great you found it yourself

please mark it solved if you got correct answer
thnx

please mark this solved if you got your answer

thnx

hai,

java.sql.Time or java.sql.Date both are perfect(as of my knowledge)

but in this case you go for java.sql.Time
try like this

java.sql.Time t = rs.getTime();
SimpleDateFormat sdf = new SimpleDateFormat("hh:mm:ss");
sdf.format(t)  // return string  

check it once

note : pls post output too incase if you haven't got the output as you expected

[modified]

yeah Neha290791,

if the data type is of date or datetime type

try to do as follows

first get the column value

your_date = rs.getDate("open_time");

then use SimpleDateFormat class to display the time as you like (as follows)

SimpleDateFormat formatter = new SimpleDateFormat("your_format_here");
formatter.format(your_date);  // returns string then display it whareever you want 

check it once and let me know the status

happy coding

@Neha290791,

could you post structure of the table?

but you are talking about time column and you are displaying/getting that data by using rs.getString() instead of using rs.getDate()

so i need data type of open_time column of your table.
[modified]

hai BoDuke1835

i think you are operation form is not like this

if (BMI = > 18.5 && BMI < 24.9)

i guess its like this

if (BMI >= 18.5 && BMI < 24.9)

try to change it as above

check it once

let me know the status

hai Neha290791,

could you post the code how you get the date data from database?

so that we try to give a way to solution

you may use shortcut.js as pritaeas said

the following url gives the full description about handling combination/short cut of keys using java script

http://www.openjs.com/scripts/events/keyboard_shortcuts/

but its java script library

i dont know whether it is your exact solution or not

let me know if you have doubts

hai riahc3,

i think this code will help you (this code can handle the Alt + k combination key event)

<script language="JavaScript" type="text/javascript">
 var isAltPressed = false;
 document.onkeyup=function(e){   
    if(e.which == 18) 
       isAltPressed=false; 
 } 

 document.onkeydown=function(e){  
     if(e.which == 18) isAltPressed=true; 
     if(e.which == 75 && isAltPressed == true) { 
            alert(" Alt + k is pressed" ); // or do whatever you wnat
            //return false;  // incase if you click predefined shot cut key combination
     } 
}
</script>

let me know if you have any doubts

happy coding

hai toldav,

yeah thats exactly correct what JamesCherrill said,

in simple words(as of my knowledge),

Note 1:

if the instantiation of a class is necessary,then its better to make the methods of that class as instance methods only.

Note 2:

if the instantiation of a class is not necessary then its better to make the methods of that class as static methods only

reason is same as described by JamesCherrill

my apologies for my poor written skills

i hope that you got the point.

happy coding.

any comments are appreciated...........................

i think it may be $clientcom reference

try to use that reference in mysql_query($query,$clientcom) function

because in your first post you called GetMarks() method by using client connection

getmark.php
<?php
//import connection file and appropriate php file
$con=new server();
$client1=new client();
$con->connect();
$x=$client1->GetMarks();
?>

so thats the reason you have to pass $clientcom reference

check it once and let me know the status

happy coding

hai solomon_13000,

this is just suggestion only :

i think that might be problem with your class couldn't find the path what you specified for ImageIcon class Objects

so try to change the creation of ImageIcon class Object like as follows at line no 11 and 12 in your code

ImageIcon ONE = new ImageIcon(getClass().getResource("/IFDesign/images/green.jpg"));

check it once and also do same for the remaining image icons creation code

let me know the status

happy coding

i think you need to pass connection reference to mysql_query() function as follows

$query=mysql_query("SELECT users.name, marks.MarksHighest FROM marks,users WHERE marks.name=users.name ORDER BY MarksHighest ASC",**$your_conn_reference_here**);

check it once

let me know the status

what i mean is your php page also (paste the php page code here)

because we will check whether you are calling the html input element values in javascript properly ot not

hai afidah,

could you post your code here?

so that it will be easy for us to give a solution

we know you got stuck at java script

yeah you are right

hai techyworld,

if you dont have any parameter then remove the entry from the $ajax() request like as folows

 $.ajax(                       // this is also valid ajax call 
 { 
   url:"marks.php",
   type:"POST",
   dataType: "json",
   success:function(data){
    //do something.
   }
};

passsing data to the resource is not compulsarily in ajax concept (based on your requirement you need to pass those data values to the particular resource)

go through the following url it will explains different modes of $ajax() calls

http://api.jquery.com/jQuery.ajax/

let me know if you have any doubts in my clarification

happy coding

hai waqar100,

as of my knowledge AJAX is concept where you want to provide synchronous/asynchronous communication between two pages with out submit the page dynamically.

we can use this concept in jquery as well as in java script because these two are scripting languages

but i dont know exactly what does it mean 'jquery in place of AJAX'

lets see, what will say our experts here?

hai toldav,

can you post the details of LinearEquation class once here? (if you have no problem)

so that we try to give a way of solution

as harinath_2007 said

you have to call doSet(ApplicationForm myApplicationForm) method before calling connectMeToDatabase(ApplicationForm myApplicationForm) method
at where you are calling these methods

at line 8 you have declared but not instantiated yet

try to call doset() method before calling connectMeToDatabase() method

let me know if you have any doubts in my clarification

thats it

happy coding

hai rouse

i am confused about one thing as shown bellow

In the display the two <div>s are stacked vertically which is one of the problems

could you explain me clearly about the requirement?

and in the second thing,

you have seen some red marks right

its border style which applied by css class for your two divs called pictureBoxRight,pictureBoxleft

go in your css and find for the classes of both divs (bellow is what you are given in your css):

pictureBoxRight {
    display: block;
    width: 500px;
    height: 475px;
    border: 1px solid red;   // this css property makes that red borders around divs on your page
    padding: 0.2em;
    float: right;
}
pictureBoxLeft {
    display: block;
    width: 450px;
    height: 475px;
    border: 1px solid red; // this css property makes that red borders around divs on your page
    padding: 0.2em;
    float: left;
}

if you want to change that then try to change the border property as follows

border: 1px solid red(or) blue (or) black; // whatever color you want here 

(or)

border:none; // set this, if want no borders around divs

let me know the status

happy coding

**any comments are appreciated on my clarification **

hai Tewhano

have you included the scripts which is relating to getting datetime and get-map() methods in the above post while running the page?

i mean your final script would be like as follows

 <script type="text/javascript">
    var timeStr = showDateTime(); 
    var mapNum = get-map();
    document.getElementById("sky").src= "sky' + mapNum + '.jpg";
    document.getElementById("datetime").inneHTML= timeStr;
</script>

please check it once

let me know the status

hai Tewhano

instead of this in your code

    <div id="maps">
    <!-- <img id="sky" src="sky0.jpg" alt="" /> original code to be replaced by the script -->
    <script type="text/javascript"
    document.write('<img id="sky" src="sky' + mapNum + '.jpg" alt=" " />');
    </script>
    <img id="mask" src="mask.gif" alt="" />
    <div id="datetime">
    <script type="text/javascript">
    document.write(timeStr);
    </script>
    </div>
    </div>

try to replace code (like this)

    <div id="maps">
        <img id="sky" src="sky0.jpg" alt="" />  <!-- this is justsetting for intial image to display -->
        <img id="mask" src="mask.gif" alt="" />
    <div id="datetime">
       // date time content is to display here 
    </div>
    </div>       
    <script type="text/javascript">
        document.getElementById("sky").src= "sky' + mapNum + '.jpg";
        document.getElementById("datetime").inneHTML= timeStr;
    </script>

check this let me know the status

and also let me know why you are used <img id="mask" src="mask.gif" alt="" /> this image ?

happy coding

hai chandub,

this is not correct place to ask questions like above

this is related javascript/DHTML/Ajax forum only

but your question is related JAVA forum

pls redirect your requirement post in JAVA forum of daniweb

you may get help from there

happy coding

hai MICHAEL,

go through the following URL

http://www.daniweb.com/software-development/java/threads/449703/randomnumber-without-duplicate

read the bguild post there (i feel thats the great solution for this kind of requirement and make that logic as you needed)

it may helps you for requirement (Random Numbers without duplicates)

happy coding

my apologies to all of you for giving this kind of response for the above requirement

hai MICHAEL,

colud you explain me clearly what you are going to do
whether you want 5 random numbers between 0 to 78 or something else

can you make me clear on this requirement

so that we are here to help you

happy coding

please go through the following URL it may helps you for this requirement

http://www.oraclenerd.com/2011/09/drop-database.html

happy coding