Posts by pzuurveen

You can install plugins for both

This is codeIgniter code. I'm unfamiliar to codeIgniter so I cant help you.

I did an echo ord('¤'); and found the correct ascii-code to be 164 so use $delimiter=chr(164);

note to self: "don't do any visual lookups and have eyes checked"

Please post more code

be carefull what your asking, you might get it :-)
this will take some reading.....

have you tried using

$delimiter=chr(207);
while ($data = fgetcsv($csvfile,1000,$delimiter,'|'))

I'm not sure what you are asking.
Please post more code

I think the trouble is in your database design:

the tables are not related

And yet they are. Put a foreign key(category_id) to table1 into table2.
If you have 2 living rooms you have 2 rows in table2.
Than do somthing like this

SELECT table1.interior_category_desc, table2.* FROM table1, table2 WHERE table1.interior_category_id=table2.category_id 

You can't use table2.interior_room_desc for this because you can have multiple category's with the same interior_category_desc (probaly from diverend houses)
also notis that you can use the table1.interior_category_desc making table2.interior_room_desc redundant.

nice little artical about database normalization

http://www.tomjepson.co.uk/mysql-select-from-table-where-date-today/

You have to send a Content-Type:multipart/mixed email
see 3e example

contact your server provider
You server is configured to save cookys to /var/chroot/home/content/96/9375396/tmp/
But that diretory appears not to exist

I don't think // is a valid mysql comment as you use at line 70:

web_customised_partners_case_study ON web_customised_partners.web_customised_partners_id = web_customised_partners_case_study_id // fix this join

check the value of
$request->getPost('remember')

You have to process the form yourself and create an html-email
look at example 4 from function.mail

or
https://dev.skype.com/skype-uri/skype-uri-tutorial-webpages

basicly php tells your webserver how to create a html-page that gets sent to the browser

You'r looking for
mysql-real-escape-string

<select onChange="openOffersDialog(this.value);

This calls a javascript function not php

session_register deprecated as of php5.3.0 and removed as of php 5.4.0.
use:
$_SESSION

also if you pass the userename by $_SESSION wha also pass it in the url?

It a template, for what?
It probley means that it is an included file.

Currently, each of these divs call a seperate page which pulls data from a MySQL database.

Why not make one ajax-call for all the div's at once to one singe php making one MySQL search?

before you load your images in you php-file
ini_set('memory_limit','16M');

I don't see the transformation between the two.
What are you trying to do?

Atleast show us the code you have sofar

because you removed the type

var icon = customIcons[type] || {};  // will be empty 
var marker = new google.maps.Marker({
map: map,
position: point,
icon: icon.icon,      // this will be emtpy
shadow: icon.shadow    // this will be empty
});

so you put a marker on the map without an icon.
fix:

var marker = new google.maps.Marker({
map: map,
position: point,
icon: customIcons.home.icon,
shadow: customIcons.home.shadow
});

on http://www.opensourcecms.com/
You can test and trie out allot off different wiki's, blogs, forums, image galleries, ...

yes, use imagecopyresampled
but you know and use that already so what is the questin?

check out
http://nl1.php.net/manual/en/session.examples.basic.php

http://www.w3schools.com/php/php_sessions.asp

I think you look for a custum Post type for use in a plugin

are you moving your old blog to the new installed?

if (isset($_POST['submit']))
    {
    // form submited so prosses the results
    // and put them into the db
    // tell the user succes or fail 
    }
else
    {
    // form not submited so lets display it
    ?>
    <form ...
    </form>
    <?
    }

the compete guide on dates :http://www.hunlock.com/blogs/Javascript_Dates-The_Complete_Reference

your $_POST variables don't exist until after you submit your form

You can use isset($_POST['submit']) to check if your form has been submited

also take a look at mysql_real_escape_string

remove the space between li and :hover in the css

#navMenu ul li:hover ul{

5000+ rows and 13000 populated fields

sound like a job for the database itself. It's designed to handle large amount of data.
In php you can run into memory problems and/or long prosessing times.
and sending it all over the net so that javascript can handlel it, will increase load times

StrobeMediaPlayback has a test stream.
change your flashvars to:
src=http://mediapm.edgesuite.net/osmf/content/test/manifest-files/dynamic_Streaming.f4m (2x)
to test your player.
If this works you know that the problem is with your server.

This should be better

    var element = document.createElement("select");//create select element
    element.setAttribute("name", "text");
    var option = document.createElement("option");//create option element
    <?php
    //Server= localhost, Username= root, pasword = "there is no password" and db name = bsc_db.
    mysql_connect('localhost', 'root', '') or die('Connection could not be established');
    mysql_select_db('bsc_db') or die('Database is not present');
    $q = mysql_query("SELECT * FROM doctor_t");

    while($r = mysql_fetch_array($q))
        {
        ?>
        option.text = '<?php echo $r['dname'];?>';//option text attribute
        option.value= "<?php echo $r['id']; ?>";
        try {
            element.add(option, null); //Standard
            }
        catch(error) {
            element.add(option); // IE only
            }
    <?php } // end while ?>
    cell1.appendChild(element);

This code will put the same value's of the first emplyee into the varables $num times?
To create a list of all employee's that match the search put the mysql_fetch_array and the html-part inside the while loop

All you need is to imbed a flash-video player and pass the video stream form your media server.
that's all html
here an example using the openscoure StrobeMediaPlayback.swf

<div>
<object width="320" height="240">
<param name="movie" value="StrobeMediaPlayback.swf"></param>
<param name="flashvars" value="src=rtmp://url_to_your_server_here"></param>
<param name="allowFullScreen" value="true"></param>
<param name="allowscriptaccess" value="always"></param>
<embed src="StrobeMediaPlayback.swf" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="470" height="320"
flashvars="src=rtmp://url_to_your_server_here">
</embed>
</object>
</div>

why not use substr and strpos?

The way you have it now:
$answers = $_POST['selected_answers0'] answer to question 0
$answers = $_POST['selected_answers1'] answer to question 1
$answers = $_POST['selected_answers2'] answer to question 2

if you change line 65 to

    echo "<input type=\"radio\" name=\"selected_answers[{$questionNr}]\" value='\"' />";

the result will be in $answers = $_POST['selected_answers']
this is an array, the index will be the number of the question and you can do a foreach-loop

i think there is an error in the mysql query: there is no WHERE part.

what is te respone if change line 17 to:

$result = mysqli_query($con,"SELECT add_delete_record.content, handover.shipment_type FROM add_delete_record, handover ") or die(mysqli_error($con));

1. You do notting with the return value

       function bookmark() {
       var pageNum = 2;
       var xmlhttp;
       if (window.XMLHttpRequest)
       {
       xmlhttp = new XMLHttpRequest();
       }else{
       alert("Not assigned!");
       }
       xmlhttp.onreadystatechange=function()
           {
           if (xmlhttp.readyState==4 && xmlhttp.status==200)
               {
               document.getElementById("myDiv").innerHTML="we got back: "+xmlhttp.responseText;
               }
           };
       var url="Bookmark.php?pageNum="+pageNum;    
       xmlhttp.open("GET",url , true);
       xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); 
       xmlhttp.send();
       alert("Bookmark send!");
       }
   
   <form>
       <input type="button" value="Bookmark" onclick="bookmark();">
    </form>
   <div id="myDiv"></div>
   

2. your php should be

   $pageNum = $_GET['pageNum'];
   echo "Page numbers: $pageNum";
   

3 change input type from submit to button

If you don't have a variable like $v['id'] or $v['idnr'] you cal alway count the questions yourself

$questionNr=0;    
foreach($qas as $k=>$v)
    {
    echo "<input id='question$questionNr' style='width:40%' type='text' 
                value='".$v['question']."' name='questions[]' >";
    echo '<br /><br />';
    foreach($v['answers'] as $answer)
        {
        echo "<input type=\"radio\" name=\"selected_answers$questionNr\" value='\".$answer.\"' />";
        echo "$answer";
        echo "<br/>";
        }
    $questionNr++;
    }

you need to add each option-element to the select-element separately.
So put the element.add insde the while loop:

    var element = document.createElement("select");//create select element
    element.setAttribute("name", "text");
    var option = document.createElement("option");//create option element
    <?php
    //Server= localhost, Username= root, pasword = "there is no password" and db name = bsc_db.
    mysql_connect('localhost', 'root', '') or die('Connection could not be established');
    mysql_select_db('bsc_db') or die('Database is not present');
    $q = mysql_query("SELECT * FROM doctor_t");
    $options = '';
    while($r = mysql_fetch_array($q))
        {
        $options .= '<option value="'.$r['id'].'">'.$r['dname'].'</option>';

        ?>
        option.text = '<?php echo $options;?>';//option text attribute
        option.value= "text";
        //option.value = "name";//option value attribute
        try {
            element.add(option, null); //Standard
            }
        catch(error) {
            element.add(option); // IE only
            }

   <?php  } // end while ?>  
    cell1.appendChild(element);

is this script part of product.php?

missing the that prosses the results
The part with either $_POST, $_GET, or $_REQUEST

You should change the name of radiobutten for each questing
something like:

echo "<input type=\"radio\" name=\"selected_answers".$v['idnr']."\" value='\".$answer.\"' />";

$v['question'] probably has spaces, so don't use that.
do something simular for the id of the input statement, id supposed to be unique. (line 3)

google:
http://www.echoecho.com/htmlforms09.htm
http://www.html-form-guide.com/php-form/php-form-checkbox.html
http://stackoverflow.com/questions/2268887/php-checkbox-input

Yes, this is missing a lot. Is this all you got?

Do you main like this ?

take a look at this:

$_SERVER

to check for mysql errors:
mysql_query("the query to test")OR die(mysql_error());