- Upvotes Received
- 1
- Posts with Upvotes
- 1
- Upvoting Members
- 1
- Downvotes Received
- 0
- Posts with Downvotes
- 0
- Downvoting Members
- 0
|
i want to view image as tooltip of small image on mouseover on that so what is the code for that?using javascript how it can be done?
|
|
|
i want to view image as tooltip of small image on mouseover on that so what is the code for that?using javascript how it can be done?
|
|
|
ajax_example1.php <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>Untitled Document</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> <script language="javascript"> function showdetail(id) { //var xmlhttp; //if(window.XMLHttpRequest) xmlhttp=new XMLHttpRequest(); /*else if(window.ActiveXObject) xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");*/ xmlhttp.open("GET","data_fetch.php?id="+id,true); xmlhttp.send(null); xmlhttp.onreadystatechange=function() { if(xmlhttp.readyState==4 || xmlhttp.readyState=="complete") { //if(xmlhttp.status==200) { //if(xmlhttp.responseText!='') { //document.getElementById('emp_nm').innerHTML=xmlhttp.responseText; xmldoc=xmlhttp.responseXML; document.getElementById("emp_nm").innerHTML=xmldoc.getElementsByTagName("emp_nm")[0].firstChild.data; document.getElementById("dpt_nm").innerHTML=xmldoc.getElementsByTagName("dpt_nm")[0].firstChild.data; document.getElementById("wrkphour").innerHTML=xmldoc.getElementsByTagName("wrkphour")[0].firstChild.data; document.getElementById("sal").innerHTML=xmldoc.getElementsByTagName("sal")[0].firstChild.data; document.getElementById("ph_no").innerHTML=xmldoc.getElementsByTagName("ph_no")[0].firstChild.data; …
|
|
|
Hi guys...Good morning...I have following code. <?php $pid=$_GET['pid']; $conn=mysql_connect('localhost','root','') or die("Cannot connect to server"); mysql_select_db('developer',$conn) or die("Cannot connect to database"); $sql="select cnode,item,pnode from listviews where cnode='$pid'"; $res=mysql_query($sql) or die("Cannot execute query"); while($ar=mysql_fetch_array($res)) { $itm=$ar[1]; $pid=$ar[0]; } $sql="select cnode,item,pnode from listviews where pnode='$pid'"; $res=mysql_query($sql) or die("Cannot execute query"); echo "<table border='1'>"; … 
|
|
|
Hii I have a query...I am using PHP,Mysql and Javascript.. I want to add values in the listbox from textbox..and also display them in hirerachical manner using treeview or <li> tag...so please send me code for performing this process. Thank you..
|