Posts by gerard4143 - Page 7

Dude have you even tried my code? "hello," is gone and friend remains. Now, all i want is ",friend" gone and hello to remain.

Anyone else?

Actually nothing is gone. All you did was take a section of the string and create another string from it....dude.

#include <iostream>
    #include <string>
    using namespace std;
     
    int main()
    {
    char comma = ',';
    string str1 = "hello,friend";
    string str2 = str1.substr(str1.find(comma)+1, str1.length()); //i guess this line...
    cout << str2 << endl;
    cout << "original string->" << str1 << std::endl;
	//system("pause");
    return 0;
    }

Try googling C++ string erase.

Whats so bad about global vareable?

Here, more google nonsense.

http://stackoverflow.com/questions/484635/are-global-variables-bad

Just tried this and it works..

using System;

namespace testit
{
	class MainClass
	{
		public static void Main (string[] args)
		{
			Console.WriteLine( inputMethod() );
		}
		
		public static float inputMethod()
        {
            float temp;

            if (float.TryParse("1234.45".ToString(), out temp))
            {
               return temp;
            }
            else 
            {
            	return 0.0f;
           	}
        }
	}
}

Try running this code

#include <stdio.h>

int main(void)
{
   float i=3.3;
   
   fprintf(stdout, "%f\n", i - 3.3);
   fprintf(stdout, "%f\n", 3.3 - i);
  return 0;
}

try

float.TryParse(txtInitialTemp.Text, out temp)

Declare the variables globally.i.e before main()

Yikes...Is that good advice?

Try reading up on references or pointers. I would try references first before plunging into pointers.

Simple reference example.

#include <iostream>

void square_it(int & i)//pass by reference
{
  i *= i;
}

int main()
{
  int i = 5;
  
  std::cout << i << std::endl;
  
  square_it(i);
  
  std::cout << i << std::endl;
  
  return 0;
}

people i still cant figure out the problem :O

We can't figure out what the problem is...Posting a chunk of code and stating that it doesn't work and then giving a brief but confusing explanation doesn't help us.

what all should i include to make it look decent?

A lot of work....

If you not comfortable with iterators then try

#include <iostream>
#include <string>
#include <iterator>

int main(int argc, char**argv)
{
  std::string str("This is the string to work with");
  
  std::cout << str << std::endl;
 
  str.erase(0, 8);
  
  std::cout << str << std::endl;
  return 0;
}

And how would this be done?

You read the above post?

Heres the thing, I don't want to remove part of the string with values (example +1, -7). Isn't there a way I can find the comma (,) within the string and remove it and whats before it?

Sure, just find what position the comma resides and then erase everything up to it.

Try googling C++ string or check this link

http://www.cplusplus.com/reference/string/string/erase/

Here's an example

#include <iostream>
#include <string>
#include <iterator>

int main(int argc, char**argv)
{
  std::string str("This is the string to work with");
  
  std::cout << str << std::endl;
  
  std::string::iterator begin = str.begin();
  std::string::iterator end = str.begin() + 8;
  
  str.erase(begin, end);
  
  std::cout << str << std::endl;
  return 0;
}

So it seems like I should use a DLL, but how do I use a DLL?

That's operating system specific...Which operating system are we talking about here?

I would try a static member function in myclass to construct the 'hidden' class.

Try initializing your array elements before you pass them to your function....Just like your error message indicated.

Didn't work sir. The output would be "Your bill is Php0.0".

Try assigning something to TP.

Try initializing TP to 0.0.

Is there any way to test if a string is an integer without having to convert the C++ string to a C_string?

std::string my_str = "123abc";


for (int i = 0; i < my_str.length(); ++i)
{
if (isdigit(my_str[i]))
{
//do something
}
}

If your trying to pass a function pointer, use typedef and it'll simplify your code.

typedef void (*myfunc)();

void thefunc(myfunc p)
{
//...
}

You'll have to investigate the stream character by character using isdigit().

Take a read here

http://www.newty.de/fpt/fpt.html#r_value

Especially the section - 2.7 How to Return a Function Pointer ?

Where's your constructor that accepts three integers?

It should be

fraction fraction::addFractions(fraction two)
{
//...
}

Try reading how to create function in C++

You have this.

float calcManagerGross(float)//??????float what?
{
     float rate, gross; 
     gross = 40*(rate); 
     return(gross);    
}

How could you write ~ 300 lines of code and not once check if the code was producing correct results?

If you want to isntall Code::Blocks for Windows go here

http://sourceforge.net/projects/codeblocks/files/Binaries/10.05/Windows/codeblocks-10.05mingw-setup.exe/download

It should start downloading Code::Blocks with the GNU gcc compiler...Note I would uninstall your previous Code::Blocks first.

Maybe you could isolate one function and that function call that produces the zeros and post that...Posting ~ three hundred lines of code and saying it doesn't work - fix it please - is infuriating.

Take a look at your braces in your if statement.

Try this

bool checkNumber(int arr[], int value)
{
	for(int i=0; (i < 10); i++)
	{
	  std::cout << arr[i] << std::endl;
		if(value == arr[i])
		{
			return true;	
		}
	}	
	return false;
}

I would read the contents of this link

http://www.cplusplus.com/reference/string/string/

I would really pay attention when you get to the string's method find.

Well try including the header cctype and using the function

int isdigit(int c)

and how can i rearrange this using a for loop

Why would you use a for loop? The purpose of a for loop is to iterate over a collection of data a fixed number of times...If you want a for loop to behave like a while loop then try this.

for(;;)
{
break;//break on some condition
}

Hint.

Don't use gets its a dangerous function. Instead use fgets().
Don't use magic numbers like 100 use a macro like

#define ARR_SIZE 100

Also

int *k;

Should be

char *k;

If your an experienced programmer(Java/C++) then C# 4.0 in a Nutshell by Joseph Albahari, Ben Albahari is a good read.

What part of the program are you having problems with? I ask because a C program is mostly a C++ program.

Try passing the values as references.

Wow another on posting a homework assignment...Please read the forum rules about posting homework assignments.

What about them?[

How many processes will run ?
And which ones?

I told you, in the code you posted, only one thread is running.

And what about processes?

What about them?

Number one, The code doesn't run in a compiler. The code is compiled by the compiler so that it can run within an operating system environment.

How many threads? Just one, the main thread.

What's your copy constructor look like?

I would drop all the references to pointers(* &) and just use references like the above posting.

Why are you using a reference to a pointer in your equals operator?

Thought so, I was hoping I could force it to be a char...

You could cast it to character.

#include <stdio.h>

#define NINE (char)0x39

int main()
{
  fprintf(stdout, "%c %lu\n", NINE, sizeof(NINE));
  return 0;
}

Sorry its against the forum rules. You must first post your attempted code and any questions.

Really what the hell does messy and glitchy mean? If you want to show use what the proper output is supposed to look like then post a copy of it...messy and glitchy means nothing from our point of view.

Are posting your homework assignment?

Try creating a pipe. Here's a simple example.

#include <iostream>
#include <unistd.h>

enum PIPES {READ, WRITE};

int main(int argc, char**argv)
{
	int hpipe[2];
	pipe (hpipe);

	if (fork())
	{
		close (hpipe[WRITE]);
		
		int x = 0;

		while (true)
		{
			read (hpipe[READ], (char*)&x, sizeof(int));
			if (x < 0) break;	
			std::cout<<"child recieved->"<<x<<"\n";
		}

		close (hpipe[READ]);
	}
	else
	{
		close (hpipe[READ]);
		const int MINUS = -1;

		for (int i = 0; i < 1000; ++i)
			write (hpipe[WRITE], (char*)&i, sizeof(int));
		write (hpipe[WRITE], (char*)&MINUS, sizeof(int));
		close (hpipe[WRITE]);
	}
	return 0;
}

Try the escape sequence \" e.g.

std::cout << "this is a quote \"" << std::endl;

Your for statement is set up wrong.

for(int x=1, y=0; y < 5, x < 15; x++, y++)

Are you sure you want your condition part of a comma operator?

Try running this code.

#include <iostream>

int main()
{

  for (int i = 0, j = 0; i < 5, j < 15; ++i, ++j)
  {
	std::cout << "i->" << i << " j->" << j << std::endl;
  }
  return 0;
}

According to the link, its stored as an int.

http://cpp.comsci.us/etymology/literals.html