A.R. Rehman Songs
Indian devotionals...
Shanti C 106 Posting Virtuoso
Shanti C 106 Posting Virtuoso
Shanti C 106 Posting Virtuoso
Shanti C 106 Posting Virtuoso
A.R. Rehman Songs
Indian devotionals...
use explode function..
Assume $_POST is your form textarea name.
see this:
$names = explode(",", $_POST['textareaname']);
print_r($names );
foreach($names as $key=>$value)
{
echo $value;
}
try this:
RewriteRule ^album/(.*)(/?)$ /viewAlbum.php?aid=$1
A mind troubled by doubt can not focus on the course to VICTORY...
- Arthur Golden.
use update query to replace that string.
Assume photos is your table and imageurl is your field..
Take backup of your table before update all these..
try this:
update photos set imageurl = replace(imageurl,'http://domain.com/','')
If you dont' want to update in your database..
then try some php string functions str_ireplace() to replace that string in image path..
What data type you have specified for your points field in your database..
post your table structure and your query...
Try this:
RewriteEngine On
RewriteRule ^(.*)$ /index.php?page=$1 [L]
The link in the url will not be changed its self,
you should have to give http://example.com/images instead of http://example.com/index.php?page=images all in your application pages...
So that end user can access with your desired link.
For some reason, it acts like the session variable was not created.
My current output: (domain/index.php?page=portfolio&view=#)
Quote ...ERROR: NULL VARIABLE
My expected output: (domain/index.php?page=portfolio&view=#)
Quote ...TEST
First test your session is created or not..
like this:
session_start();
if($_GET['view'] == 0){ // URL would be domain/index.php?page=portfolio&view=0
$_SESSION['catImages'] = array();
$_SESSION['catImages'][0] = "TEST";
} else { // URL would be domain/index.php?page=portfolio&view=#
if(isset($_SESSION['catImages']) && !empty($_SESSION['catImages']))
echo "Session not created";
else
echo $_SESSION['catImages'][0];
}
First , this thread is not at all related to PHP,
and many codes available in google for this..
Just try with some code and come here for suggestions..
the below is the code for disabling a button:
document.myform.mybutton.disabled = true;
Write onclick function for your form checkbox and validate whether this is check or not, if it is checked then disable your button by the above code..
Please make a try on this and come up with your code if it not work..
Happy new year too...
You have to increment session login_counter before redirect to the Main_Login.php page..
see this:
if(!isset($_SESSION['txtusername']))
{
session_register("txtusername");
session_register("txtpassword");
session_register("login_counter");
$_SESSION['login_counter']=0;
$_SESSION['txtusername']="";
header("location:Main_Dashboard.php");
}
else
{
$_SESSION['login_counter']=$_SESSION['login_counter']+1;
header("location:Main_Login.php");
}
}
and put this code in Main_Login.php page:
if(isset($_SESSION['login_counter']) && ($_SESSION['login_counter']==3))
{
echo "Please wait for some time!";
}
try this:
if($count==1)
{
if(!isset($_SESSION['txtusername']))
{
session_register("txtusername");
session_register("txtpassword");
session_register("login_counter");
$_SESSION['login_counter']=0;
$_SESSION['txtusername']="";// intialize name
header("location:Main_Dashboard.php");
}
else
{
$_SESSION['login_counter']=$_SESSION['login_counter']+1;
}
}
and to validate:
if(isset($_SESSION['login_counter']) && ($_SESSION['login_counter']==3))
{
echo "Please wait for some time!";
}
just intialize a session with username and logincounter like $_SESSION and $_SESSION
for every try increment the logincounter session for the same username..
if its greater than 3 then dont' allow for login..
or post your code, we will check it out..
if($count==1)
{
session_register("txtusername");
session_register("txtpassword");
header("location:Main_Dashboard.php");
}
You have written session_register("txtusername");
But no where assigning value in it like $_SESSION="name";
in logout page:
unset($_SESSION);
where do you defined $_SESSION in your code..
If you got any errors, plz post here...
Try this:
function doOperation()
{
static $x=0;
static $y=0;
static $z=0;
$y=$x;
$z=$z+$y;
echo "X: ".$x."<br>";
echo "Y: ".$y."<br>";
echo "Z: ".$z."<br>";
echo "------<br>";
$x=$x+10;
}
doOperation();
doOperation();
doOperation();
doOperation();
doOperation();
remove slash after file name which comes from $post–>post_name;
$data is multi-dimensional array..
try to print like this:
print_r($data[0]);
print_r($data[7]);
As i understood,
see this code:
<script type="text/javascript">
function change_send(x)
{
//alert(x);
window.href="page2.php?text="+x;
}
</script>
<html>
<p>
<table>
<tr>
<td>
Your full name:</td>
<td>
<input type="text" name="fullname" onChange="change_send(this.value);"></td>
</tr>
</table>
</html>
or come up with clear information.
or
After getting date from calender in dd/mm/yyyy format , change this format to yyyy-mm-dd. it is not so difficult..
and then write it in your sql query.
In which folder you uploaded the .htaccess file in webserver.
and what have you written in .htaccess file..
you have to pass $q to the function fetch() not $data..
mysql_fetch_array() function only takes resource returned by mysql_query() function.
or change your fetch() like this:
function fetch($data)
{
$q = mysql_query($data);
mysql_fetch_array($q);
}
A ClassNotFoundException means that some where a class that is used in the code is missing.
check for that file..
1.check whether control is going to if or else..Keep echos in two conditions.
2.Try to print
$row
value before if condition.
3.print cookie value after else..
4. also try this setcookie('LoginIdCookie',$LoginId,time()-3600);
5.for logout coding why you are checking the id with database(as it is already done in login code).
thank you
User(fname, lname,email and userid ------primary key{userid} )
Exam( examid, examname,categoriid-------primary Key{examid})
Exam_user(examid, userid------
Exam_category(categoryid, categoryname----prmary key{categoryid})
you can write:
select u.fname,u.lname,u.email,c.categoryname,e.examname from user as u,exam as e,exam user as eu,category as c where u.userid=eu.userid and eu.examid=e.examid and e.categoryid=c.categoryid;
the above is vary basic query, try inner joins to be more specific..
read joins tutorial in google..
try to quote your post values like this:
'".$_POST['a_id']."'
means
your query should like this:
mysql_query("insert into patient_information (ID,admission_ID,patient_ID,guardian_ID,admission_date,admission_time,patient_status,reason_for_status,referred_doctor_ID,referred_doctor_name,assigned_doctor_ID,assigned_doctor_name,department_ID,department_name,ward_ID,ward_no,room_ID,additional_notes) values('NULL','".$_POST['a_id']."',..etc
or try to echo your query like:
$q="insert into ...."; // your query
echo $q;
see that query and post here
set ag_code field to null in your data base table or try to insert null value for ag_code like:
INSERT INTO auditor_only(ag_title,ag_code) VALUES("awefwefaa","")
And check these type of fields any more in your table and set them for null..
or post your structure of table..
post necessary code we will check it out..
use sessions to do login and logout pages.. and contact display page only for logged in members..
your code is perfectly fine...
As per priteas insert these lines:
$submit = isset($_POST["submit"]) ? true : false;
if ($submit)
{
// your code
}
or try to print this:
if($_SERVER['REQUEST_METHOD'] == "POST")
{
print_r($_POST);
}
try once and post the error what exactly you got.
check whether you are using post or get in form tag..
First try to google and start coding.. Then any problem occur come here for suggestions..Not for doing your home work..
try this:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
</HEAD>
<BODY>
<SCRIPT LANGUAGE="JavaScript">
function add_val()
{
ival=document.getElementById('ivalue').value;
test.testselect.options[test.testselect.options.length]=new Option(ival,ival);
document.getElementById('ivalue').value="";
}
//-->
</SCRIPT>
<form action="" method="post" name="test">
<br>
<select name="testselect">
<option>One</option>
</select><br>
<br>
<input type="text" name="ivalue" id="ivalue" value="">
<br>
<br>
<input type="button" name="submit" value="submit" onClick="add_val();">
<br>
</form>
</BODY>
</HTML>
can u be little more clear?
have you used blob for your images saving in your database?
or this :
header("Content-type: image/jpeg");
$im = imagecreatefromstring(mysql_result($result, 0));
imagejpeg($im);
imagedestroy($im);
i think you wrote unnecessary code.. check it once..
Now internet is a friend.
Later its depends on our way(good/bad) of browsing.
kkjay,
use these functions will help you:
//function for image uploading
function image_upload($image_name,$img_size,$img_temp,$path)
{
if($img_size>1) //for uploading image
{
$proimg=substr($image_name,0,strpos($image_name,'.'));
$commonname=time();
$name=substr($image_name,0,strpos($image_name,'.'));
$fullname=$name.$commonname.strstr($image_name,'.');
$real_image=$path.$fullname;
if(!move_uploaded_file($img_temp,$real_image))
{
$real_image="";
}
chmod($real_image,0777);
}
return $real_image;
}
function image_resize($i_old,$i_path,$size1,$size2)
{
$image_attribs = getimagesize($i_old);
if(substr($i_old,-3)=='gif') {
$im_old =imagecreatefromgif($i_old);
} else if(substr($i_old,-3)=='png') {
$im_old =imagecreatefrompng($i_old);
} else {
$im_old =imagecreatefromjpeg($i_old);
}
$width=$image_attribs[0];
$height=$image_attribs[1];
//
$th_max_width4= $size1;
$th_max_height4=$size2;
$ratio4 = ($width > $height) ? $th_max_width4/$image_attribs[0] : $th_max_height4/$image_attribs[1];
$th_width4 = $image_attribs[0] * $ratio4;
$th_height4 = $image_attribs[1] * $ratio4;
$im_new4 = imagecreatetruecolor($th_width4,$th_height4);
imageantialias($im_new4,true);
$th_file_name4= $i_path;
imagecopyresampled($im_new4,$im_old,0,0,0,0,$th_width4,$th_height4, $image_attribs[0], $image_attribs[1]);
if(substr($i_old,-3)=='gif') {
imagegif($im_new4,$th_file_name4,60);
} else if(substr($i_old,-3)=='bmp') {
imagewbmp($im_new4,$th_file_name4,60);
} else if(substr($i_old,-3)=='png') {
imagepng($im_new4,$th_file_name4,60);
} else {
imagejpeg($im_new4,$th_file_name4,60);
}
return $th_file_name4;
//
}
just call these two functions in your for loop by passing required parameters.
call same image_resize() function for large and small images with different size parameters..
i have tested this code. working fine for me.
thanks.
try this:
<?php
$username = $_POST['username'];
$password = $_POST['password'];
if (isset($username,$password))
{
$connect = mysql_connect ("localhost","root","");
mysql_select_db("phplogin");
$query = mysql_query("SELECT * FROM `users` WHERE username ='$username' and password='$password'");
$numrows=mysql_num_rows($query);
if ($numrows==0)
{
die("Incorrect username / password");
}
}
else
{
die("please enter username and password");
}
?>
try this is working:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
</HEAD>
<BODY>
<SCRIPT LANGUAGE="JavaScript">
<!--
var emp = new Array ("Billy", "Jill", "Wolfgang", "Xavier", "Antoinette","John")
var empNum = new Array (78,90,23,12,56,31)
var i = 0
var empSearch = eval(prompt("Please Enter the ID of the employee you are looking for?"));
smsg="";
emsg="";
for(var i = 0; i < empNum.length; i++)
{
if (empSearch!=null && empSearch!="")
{
if (empNum[i] == empSearch)
{
smsg="<br> employee number is valid; this employee is " + emp[i] + "<br>";
break;
}
else
{
emsg="employee number is not valid";
}
}
}
if(smsg!="")
document.write(smsg);
else
document.write(emsg);
//-->
</SCRIPT>
</BODY>
</HTML>
try this:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
</HEAD>
<BODY>
<SCRIPT LANGUAGE="JavaScript">
<!--
var emp = new Array ("Billy", "Jill", "Wolfgang", "Xavier", "Antoinette","John")
var empNum = new Array (78,90,23,12,56,31)
var i = 0
var empSearch = eval(prompt("Please Enter the ID of the employee you are looking for?"));
for(var i = 0; i < empNum.length; i++)
{
if (empNum[i] == empSearch)
{
document.write("<br> employee number is valid; this employee is " + emp[i] + "<br>");
break;
}
else
{
//document.write("employee number is not valid");
}
}
//-->
</SCRIPT>
</BODY>
</HTML>
2) How to get the path of the window in js?
var path = document.location.pathname;
alert (path);
1) How to refresh a page in jsp even if the javascript is not supported by the browser or if it is disabled?
window.location.reload( false );
how do I resize the array of images so that i can store the 6 large and 6 thumbs in a server/folder and their locations in a database. I'm not very experienced in PHP.
I think this is regardless of array..
Try with your existing code. But name your images with different names (concatinate image name with time and large/small) and save the path in database.
All the best.
or try this :
string stripslashes ( string $str )
try this before inserting:
$answer=addslashes($answer);
No,
onclick="update_value('".$rows['itm_id']."','".$rows['totalInCart']."');"
why because the update button also repeated in for loop. Then no problem occur.
you just alert your values in js function and see if they are correct or not by clicking different update buttons.
i think you should get correct values..
you can get array of form field like this:
$uimages = $_POST['establishment_image'];
foreach( $uimages as $v )
{
// single image
print $v;
}
Be deaf while hearing negative talks...
like this:
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<%
String q = request.getParameter("q");
//String str = "Loading JSP String from Ajax: Loading......";
String[] str = {"one","two","three"};
java.util.Date dt = new java.util.Date();
for(int i=0; i<str.length; i++){
out.println(str[i]);
// Design you table here and assign strings here
out.println("<table><tr><td>......");
}
write $_GET and $_POST in for loop as you wrote for your cart items.
Then you can get your values like:
for()
{
echo $_POST[txtqty.$i];
echo $_POST[hidden_id.$i];
}
or try solution2 which is easier than previous...
Thanks.
i am not sure, but try this :
<SCRIPT LANGUAGE=javascript>
{
var Backlen=history.length; history.go(-Backlen);
window.location.href=page url
}
</SCRIPT>