simasj

If your mysql data table types are InnoDB then I think you should movie_id screen table as foreign key. InnoDB rejects any INSERT or UPDATE operationb attempts to create a foreign key value in child table so user will be denied to inserting wrong movie_id number into screens table. Your …

Maybe this link will help you: http://sgserror.com/example/submit.php

If you want that other programmers would not be able to read your code, then I will be the bad messeger: there is no way to encrypt your source code - as it must be run by php interpreter, this means that it must be decrypted at some point. So …

If you want to get more concrete answers, you should ask more concrete questions. If you want to start using MVC paradigm in php, you should read more about CakePHP or Simphony php frameworks. There are lot of more MVC frameworks, but I think those two are most popular.

So what is the problem? Data is not inserted or you php code gives error? P.S. Your code is VERY insecure! Please do at least any input data validation and sanitization.