thejimgaudet

Of the code after you run your page? I would like to see what IE and Firefox are putting into the boxes where your PHP code is.. Also, are you looping through your images?

It looks like all of your check boxes have the same name, putting them into a group. So you would only get the result of the checked box. using jQuery tho, you could loop through them and put the checked box values into one array and send that.. assuming these …

Your code?

[CODE] $result=mysql_query("UPDATE articles SET loginid='$loginid',title='$title',author='$author',body='$body',date='$today',category='$category' WHERE articleid='$getedit' LIMIT 1") [/CODE] Just use this, you had an extra ) that you didn't need...

If you give the select field a class and then run some code using jQuery, would that work for you? [CODE] $(".className").change(function() { // Your code here }); [/CODE]

that looks like your CSS file ?

I think you will need to run that PHP file through a .post() command, that will return the values you want, the session ID comes from php session, so you don't need to pass that with the post.

Well, off the top of my head I would say that you write a small PHP file that will check the count of rows in the db, like this let's call the following code count.php [CODE] <?php //CONNECT to your DB $sql = 'SELECT * FROM table;'; $result = mysql_query($sql); …