Joining integer numbers together to make new number

8 Years Ago TrustyTony

Sometimes we want to tackle some problem specifying properties of sequence of numbers consisting the integer. Then it is usefull to have function to join many integers to make a long integer. Most efficient way for tight loops is to stay in integers domain and not go through the string representation. Inspired by C++ question and my answer to it: http://www.daniweb.com/software-development/cpp/threads/425472/how-concatenate-number-in-c#post1819908

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TrustyTony 888 pyMod

IT Pro doing Eng-Fin-Eng translations

def together(*numbers):
    b = numbers[-1]
    for a in reversed(numbers[:-1]):
        magnitude = 1
        while b >= magnitude:
            magnitude *= 10
        b = magnitude * a + b
    return b

print together(123, 456, 100, 789, 10, 999, 1000, 99)

TrustyTony 888 pyMod

8 Years Ago

Code snippet updated to handle also zero values:

def together(*numbers):
    b = numbers[-1]
    previous_zeroes = 1
    for a in reversed(numbers[:-1]):
        if not a:
            previous_zeroes *= 10
        else:
            magnitude = 10
            while b >= magnitude:
                magnitude *= 10
            b = previous_zeroes * magnitude * a + b
            previous_zeroes = 1            

    return b

if __name__ == '__main__':
    print together(123, 456, 0, 0, 789, 10, 123, 1000, 99, 0)

Lucaci Andrew 140 Za s|n

8 Years Ago

you could also do it like this

def nr(*nrs):
    nr = ""
    for i in range (0, len(nrs)):
        a = str(nrs[i])
        nr = nr + a
    return int(nr)
print nr(1, 2, 3, 4, 5, 6) + 100000000

since Python works with strings alot.

and if you want to put a 0 in front, the program should ignore it.

def nr(*nrs):
    nr = ""
    for i in range (0, len(nrs)):
        if nrs[i] == '0': continue
        else :
            a = str(nrs[i])
            nr = nr + a
    return int(nr)
print nr(0, 2, 3, 4, 5, 0, 6)

thow, the int(nr) will do that, I put this to evidentiate if so the need.

Edited 8 Years Ago by Lucaci Andrew

TrustyTony 888 pyMod

8 Years Ago

As I mentioned, keeping in numbers is likely to be most efficient, but doing with strings is super simple:

def nr(*nrs):
    return int(''.join(str(n) for n in nrs))

print(nr(1, 2, 3, 4, 5, 6) + 100000000)

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