I am trying to get quite a large number 0.00012354684 to X required decimal places.
Using <iomanip> and setprecision() but I cant seem to get it to work.
Could someone please give me a small example.
Thankyou, Regards X
I am trying to get quite a large number 0.00012354684 to X required decimal places.
Using <iomanip> and setprecision() but I cant seem to get it to work.
Could someone please give me a small example.
Thankyou, Regards X
How large is X? What is the type of your large number? 0.00012354584 is actually quite small :D
number = 0.00012354684
type = float
decimal points vary = 1-5
Use double (~16 decimal digits); 32-bit floats keep only ~5-7 decimal digits.
Always use double type in math calculations!
Using <iomanip> and setprecision() but I cant seem to get it to work.
Could someone please give me a small example.
ok:
float a = 0.00012354684;
//number has 8 meaningfull digits (skip the first zero's)
cout << setprecision (8) << a << "\n";
cout << setprecision (5) << a << "\n";
cout << setprecision (3) << a << "\n";
cout << setprecision (1) << a << "\n";
output:
0.00012354684
0.00012355
0.000124
0.0001
What doesn't work in your program? Post your code.
Nice work niek_e again!
I found my problem:
- is there something I should be aware of when dividing 2 numbers in C++?
- thats why I am getting no decimal points?
Another small example, please? :)
Thankyou, Regards X
- is there something I should be aware of when dividing 2 numbers in C++?
- thats why I am getting no decimal points?
try this:
float a = 1.2, b = 0.5;
int c = 2, d = 3;
cout << "two floats: " << a/b << "\n";
cout << "two ints: " << d/c << "\n";
cout << "float and int: " << a/c << "\n";
output
2.4
1
0.6
so the answer is: yes. Dividing 2 ints will result in loss of decimal point. But that's kind of obvious right?