0

```
while (j < i)
{
cin.ignore();
cout << "Please type enter to display: ";
cin >> enter2;
if (strcmp(enter, enter2) == 0)
{
cout << "ID: " << students[j].ID << endl;
cout << "Name: " <<students[j].name << endl;
cout << "Address: " <<students[j].address << endl;
cout << "Telephone: " <<students[j].telephone << endl << endl;
j++;
}
}
j = 0;
```

Program will display all studentsâ€™ information in tabular form. Display 2 students at any one time. When user types <enter>, program then display the next 2 students,

until all students are displayed.

I'm suppose to display 2 students at 1 go, wait for user to type enter then display the other 2 students.

The problem is that I'm stuck with this particular part.

If I put

for (int z = 0; z < 2; z++)

Then there would be a problem if my array has an odd number. Hmmm what to do...