I dont want to cout the char I want pointer[a] to be the char.
I don't really understand the question but...
let p be the pointer
int *p=&a; //stores the the address of a
cout<<&p; //revels the address of P
cout<<p; //revels the address it stores
cout<<*p; //revels the information stored in the pointed address that is value of a
now if you want to show the char of a then
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