I have the following array that prints out the amount of rainfall for each month, and then uses a bubble sort to sort it in ascending order... How can I display the name of the month along with the value that is already displayed?

``````#include <iostream>
using namespace std;

void bSort(int[], int);

int main()
{
string months[12] = {"Jan", "Feb", "Mar", "Apr", "May","Jun","Jul","Aug", "Sep","Oct", "Nov", "Dec"};
int rain[12];
double total = 0;
double average;
double min = 0;
double max = 0;

for (int i = 0; i <=11; i++)
{
cout << "Input the Amount of rainfall in " << months[i] << ": ";
cin >> rain[i];
while (rain[i] < 0)
{
cout << "Cannot have negative rainfall! Please re-enter:";
cin >> rain[i];
}
}
for(int i = 0; i <= 11; i++)
{
total = total + rain[i];
}

average = total / 12;

min = rain[0];
for(int i = 1; i < 12; i++)
{
if(rain[i] < min)
min = rain[i];
}

max = rain[0];
for(int i = 1; i < 12; i++)
{
if(rain[i] > max)
max = rain[i];
}

cout << "Total Rainfall: " << total << endl;
cout << "Average Rainfall: " << average << endl;
cout << "The lowest monthly rainfall is " << min << endl;
cout << "The highest monthly rainfall is " << max << endl;

bSort(rain, 12);
for(int i = 0; i < 12; i++)
{
cout << rain[i] << endl;
}

return 0;
}``````
``````#include <iostream>
#include <cstdlib>
using namespace std;

void bSort(int intArray[], int size)
{
int rain;
bool swap;

do
{
swap = false;
for(int i = 0; i < (size-1); i++)
{
if(intArray[i] > intArray[i+1])
{
rain = intArray[i];
intArray[i] = intArray[i+1];
intArray[i+1] = rain;
swap = true;
}
}
}while(swap);
}``````
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8 Years
Discussion Span
Last Post by rudasi

Probably the simplest (and dirty) method: pass month array into the bSort function and swap its elements at the same time as rain elements swapped...

``#include<string>``

Hi,

I agree with ArkM, passing the month array at the same time and swapping it would be a good option.

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