<email snipped and color code tags deleted> this is the solution for this problem its kinda long and boring ,but it works properly
#include <iostream>
#include <iomanip>
using namespace std;
void main()
{
const int r=4, c=4;
int ar1[r][c];
int ar2[r][c];
int sum[r][c];
int prod[r][c];
int s=0, y, x;
cout<<"please enter the elements for the first (4x4) arry"<<endl;
for(int i=0;i<r;i++)
{
for(int j=0;j<c;j++)
cin>>ar1[i][j];
}
cout<<"please enter the elements for the second (4x4) arry"<<endl;
for(int i=0;i<r;i++)
{
for(int j=0;j<c;j++)
cin>>ar2[i][j];
}
for(int i=0;i<r;i++)
{
for(int j=0;j<c;j++)
sum[i][j]=ar1[i][j]+ar2[i][j];
}
cout<<endl;
cout<<" the first array is"<<endl;
for(int i=0;i<r;i++)
{
cout<<endl;
for(int j=0;j<c;j++)
cout<<setw(5)<<ar1[i][j];
}
cout<<endl;
cout<<" the second array is"<<endl;
for(int i=0;i<r;i++)
{
cout<<endl;
for(int j=0;j<c;j++)
cout<<setw(5)<<ar2[i][j];
}
cout<<endl;
cout<<" the sum of the Two arrays is "<<endl;
for(int i=0;i<r;i++)
{
cout<<endl;
for(int j=0;j<c;j++)
cout<<setw(5)<<sum[i][j];
}
cout<<endl;
for(int i=0;i<r;i++)
{
for(int j=0;j<c;j++)
{
y=0;
for(int s=0;s<c;s++)
{
x=ar1[i][s]*ar2[s][j];
y=y+x;
}
prod[i][j]=y;
}
}
cout<<left;
cout<<"the Product array is the followin"<<endl;
for(int i=0;i<r;i++)
{
cout<<endl;
for(int j=0;j<c;j++)
cout<<setw(8)<<prod[i][j];
}
cout<<endl;
}
