Hey fellas,

I have searched for this answer for about an hour on and off and cannot find anything so sorry to have to resort to posting.

I have a list [a, b, c, d]

And I want to write it to a simple output file, but I want it to be written with a new line after each character so that it appears in the file as:
a
b
c
d

There is more going on in the program but this is the only thing I really am concerned with at the moment. It's complaining when I insert a newline character into the writeout (I assume this only applies to strings).

Here is a snipet of my code if that helps:
--------------------------------------------- (Declarations separated below)
temp = [ ]

col = int(raw_input('Please select a column (starting at 0) from your infile, %s:' % (infile)))
--------------------------------------------

for line in f:
line = line.split() #Line has been split into a list of components [a,b,c...]
temp.append(line[col]) #Write the user-specified column into the empty list, "temp"

for i in range(len(temp)): #This line basically just prints one by one
o.write(temp)

Thanks for the help woooee

Hey, it helps to read the code posted in this forum if it's in code tags. And also, if you wanted to do a single write that included your newline you can do something like this:

temp = ["4", "5", "6", "7", "8"]
for i in range(len(temp)):
    f.write("%s\n" % temp[i])

However that's not very pythonic (the for loop), but this is:

for item in temp:
    f.write("%s\n" % item)

Or perhaps instead of this:

for line in f:
    line = line.split() 
    temp.append(line[col])

for i in range(len(temp)):
    o.write(temp[i])

You could simplify it and do this:

o.open(..., 'w')
o.write( '\n'.join( [ line.split()[col] for line in f ] ) )
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