How would you count how many opening HTML tags there were & then closing tags in a line?
eg
for line in something:
for match in re.match("[I]opening_regex_here[/I]",line):
# will match <H1> or <html> or whatever
opentags += 1
for match in re.match("[I]closing_regex_here[/I]",line):
# will match <H1> or </html> or </whatever>
closingtags += 1Jump to PostYou could do it as simple as this ...
html_str = """\ <html> <head> <title>Bring up an image with sound</title> </head> <body> <IMG SRC="train.bmp" WIDTH=320 HEIGHT=210 BORDER=5> <bgsound src="train.wav" loop=2> </body> </html> """ tag_close = html_str.count('</') # each close tag also has an open tag, so deduct …
You could do it as simple as this ...
html_str = """\
<html>
<head>
<title>Bring up an image with sound</title>
</head>
<body>
<IMG SRC="train.bmp" WIDTH=320 HEIGHT=210 BORDER=5>
<bgsound src="train.wav" loop=2>
</body>
</html>
"""
tag_close = html_str.count('</')
# each close tag also has an open tag, so deduct it
tag_open = html_str.count('<') - tag_close
print( "open = %d close = %d" % (tag_open, tag_close) )thanks, I ended up with:
ultimate_regexp = "(?i)<\/?\w+((\s+\w+(\s*=\s*(?:\".*?\"|'.*?'|[^'\">\s]+))?)+\s*|\s*)\/?>"
for match in re.finditer(ultimate_regexp, line):
if repr(match.group()).startswith("'</"):
etcount += 1
else:
otcount += 1I found the re on a website, thanks,
matio
Thanks, looks like this code is more precise than my simple code!
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.