How do I run a .py file from another python file....

I want a program depending upon the option you choose to run a different python program...

Ho do i do this...

I have tried:

import os
if os.path.isfile('file.py'):
    exec(open('file.py').read)

and it requires everything to be global....
only when the call line is the only thing in the file does it work perfectly...

You can execute it using the os module. In DOS or GNU/Linux, in the command line you can type python code.py to execute a file. So you can try this:

import os
os.system("python othercode.py")

The one problem would be if the user does not have "python" registered as a recognized command. Below is the universal solution which locates the user's python executable and uses a system call to that with its absolute path:

import os
import sys
pyexe = sys.executable  # something like "C:\Python25\python.exe"
os.system('%s othercode.py' % pyexe)

This should be cross-platform compatible. Hope that helped!

I would use module subprocess:

# os.system() does not allow the Python program 
# to run in the background, whereas subprocess does

import subprocess

# remove  "arg1", "arg2" if you don't have any command line args
subprocess.call(["C:/Python25/Python.exe", "Skripta.py", "arg1", "arg2"])

thanks for your help i'll try both out see what works for me....

Thank you so much.