Hello I'm new here and I've been up two night's trying to figure out how to write a program that will convert numbers to word. If anyone can help please respond to the post. here is what I sort of figured out so far. As you can tell I'm still only about 5 months into programming. I need the program to be able to do this up to 20,000.

/** Brandon Brown **/
/** 2/17/05 **/

//*ALGORITHM

#include <iostream> 
#include <fstream>
  using namespace std;
 int main() 
 { 

    int number, one ;
		 
cout << "enter number  "<< endl;
cin >>number;


	 cout << number<< "number :"<< endl;

switch (int)
 case 1:
cout << "one";

switch (int)
 case 2:
cout << "two";
 
switch (int)
 case 3:
cout << "three";
 
switch (int)
 case 4:
cout << "four";
 
switch (int)
 case 5:
cout << "five";
 
switch (int)
 case 6:
cout << "six";

switch (int)
 case 7:
cout << "seven";



return 0;
 }

You should search the forum before asking a question that's been [thread=11968]asked before[/thread].

can u cr8 me program that words converted to numbers.(1-50) using switch. pls help me.

commented: poor grammar; do it yourself. +0

Sure. Since your language's orthography apparently uses digits for any homonymous syllable, just use

(std::stringstream() << n).str()

pls post.

commented: Please use real English worlds - 'pls' is not a word, nor is cr8 -1

Sure. Since your language's orthography apparently uses digits for any homonymous syllable, just use

(std::stringstream() << n).str()

This gave me a good laugh.

plsss. i need it. can u make that program? i need it badly. pls

How do you convert numbers to words by hand? Take that algorithm and write it in C++.

Make a while loop to make a number (I called this one divisor) an multiply it by 10 till its larger than the number you're calculating.

Then in another loop, you're going to need to divide by divisor, get both the remainder AND the front digit and store them. Don't store them over n.

Then you're going to make a bunch of if statements to calculate the correct words based on the front (the current digit you're working on.) When I wrote it the total I have is 5 switch statements inside 4 if statements + some minor if statements to end the loop if there's errors or nothing else to calculate.

Here's my program:

#include <conio.h> 
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
 
char *make_words(char *s, int ncomma);
char *insert_comma(long n, int *ncomma);
char *int2words(int n);
int a;
 
int main(void)
{
 


 printf("Enter number: ");
 scanf("%d",&a);
  printf("%d = %s\n",a,int2words(a));

 
  getch();  
  return 0;
}

char *make_words(char *s, int ncomma)
{
  int i, len, rest = 0;
  char *p = NULL;
  static char zzz[256];
 
  static char *ones[] = {"one ","two ","three ","four ",
    "five ","six ","seven ","eight ","nine "};
  static char *tens[] = {"ten ","eleven ","twelve ","thirteen ",
    "fourteen ","fifteen ","sixteen ","seventeen ","eighteen ","nineteen "};
  static char *twenties[] = {"","twenty ","thirty ","forty ",
    "fifty ","sixty ","seventy ","eighty ","ninety "};
  static char *hundreds[] = {
    "hundred ","thousand ","million "};
 
  memset(zzz, '\0', 256);  // fill with nulls
  len = strlen(s);
  for(i = 0; i < len; i++)
  {
 
    if ((p = strchr((s[i] == ',') ? &s[++i] : &s[i], ',')) == NULL)
    {
      p = &s[strlen(s)];
    }
    if (s[i] == '0')
    {
      continue;  // skip one iteration
    }
    if ((rest = (p - &s[i])) != 0)
    {
      if (rest == 3)
      {
        strcat(zzz, ones[s[i] - '0' - 1]);
        strcat(zzz, hundreds[0]);

        if (len == 7 && s[2] == '0')  strcat(zzz, hundreds[1]);
        if (len == 11 && s[2] == '0')  strcat(zzz, hundreds[2]);
      }
      else if (rest == 2) 
      {
        if (s[i] == '1')
        {
          strcat(zzz, tens[s[++i] - '0']);
          rest--;
        }
        else
        {
          strcat(zzz, twenties[s[i] - '0' - 1]);
        }
      }
      else
        strcat(zzz, ones[s[i] - '0' - 1]);
    }
    if (rest == 1 && ncomma != 0)
    {
      strcat(zzz, hundreds[ncomma--]);
    }
  }
  return zzz;
}
 

char *insert_comma(long n, int *ncomma)
{
  static char zzz[30];
  int i = 0;
  char *p = &zzz[sizeof(zzz)-1];
 
  *p = '\0';
  *ncomma = 0;
  do 
  {
    if (i % 3 == 0 && i != 0) 
    {
      *--p = ',';
      ++*ncomma;
    }
     *--p = (char)('0' + n % 10);
    n /= 10;
    i++;
  } while(n != 0);
  return p;
}
 
char *int2words(int n)
{
  int nc;
  char *ps, *zzz, *minus;
  char *buffer;
  buffer = (char *) malloc(256);
 
  // save any - sign
  if (n < 0)
  {
    minus = "minus";
    n = abs(n);
  }
  else
  {
    minus = "";
  }
 
  ps = insert_comma(n, &nc);

  zzz = make_words(ps, nc);
 
  sprintf(buffer,"%s %s", minus, zzz);
 
  return buffer;
  getch();
}
commented: Thank you for resurrecting a 1.5 year old thread, AND doing his homework. -4

# include <stdio.h>
void main () {

Int N;


printf("Input number:");
scanf("%d",&N);
if
(N==1){
printf("One");
}
else if
(N==2){
printf("Two");
}
else {
printf("Invalid")
}


}

why don't you used else if?
its good but super basic...

commented: Please finish this program up to 999. -4