I am using MS VC++ '08, ad have run into a problem that stumps me :
void printtext(char **lotsoftext,int m,int n)
{
for(int i=0;i<n;i++)
for(int j=0;j<m;j++)
print(lotsoftext[i][j]);
}The error is as follows :
cannot convert parameter 1 from 'char' to 'const char *'
How do i correctly refer to lotsoftext ?
Oh, and i don't want to use 2d arrays, so please don't tell me to do that. ;)
Jump to Postshort answer : change
void printtext(char **lotsoftext,int m,int n)to
void printtext(const char **lotsoftext,int m,int n)Just a side note, when your function does not change the content of its arguments thats passed, then make
them const.
Jump to Postif it changes its values then your functions should have
a non const array as a parameter like so :void printtext(char **lotsoftext,int m,int n)but you cannot pass a const array to it because the function
does not promise not to change its content.
short answer : change
void printtext(char **lotsoftext,int m,int n)to
void printtext(const char **lotsoftext,int m,int n)Just a side note, when your function does not change the content of its arguments thats passed, then make
them const.
Thanks, that stopped the compilation errors atleast.
But suppose if i make a similar function that does change the array, how would I go about doing that?
For example,
void printtext(char **lotsoftext,int m,int n)
{
for(int i=0;i<n;i++)
for(int j=0;j<m;j++)
{
print(lotsoftext[i][j]);
if(i==2 && j==1)
lotsoftext[i][j] = "Hello";
}if it changes its values then your functions should have
a non const array as a parameter like so :
void printtext(char **lotsoftext,int m,int n)but you cannot pass a const array to it because the function
does not promise not to change its content.
okay, thanks for helping so fast.
no problem. Mark this thread solved?
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