this code takes out the spaces in between and i want to shrink this code a bit.
like in function modify. It doesnt work if i take out the if(s[i] == ' ')
I want to make this code work without using that.
Any help??

#include<stdio.h>
#include<stdlib.h>

char* modify(char*);

void main()
{
        char* str = malloc(100 * sizeof(char));
        char* mstr;

        printf("Enter a string: ");
        gets(str);

        mstr= modify(str);
        printf("String after removing spaces: %s \n\n",mstr);
}

char* modify(char *s)
{
        int i,j=0;
        static char temp[200];
        for(i = 0; s[i] != '\0'; i++)
        {
                if(s[i] == ' ')
                {}
                else
                {
                        temp[j] = s[i];
                        j++;
                }
        }
        temp[j] = '\0';
        return temp;
}

char* modify(char *s)
{
	int i,j=0;
	static char temp[200];

	for(i = 0; s[i]; i++)
	{
		if(s[i] != ' ')
		{
			temp[j] = s[i];
			j++;
		}
	}

	temp[j] = '\0';
	return temp;
}

char* modify(char *s)
{
	int i,j=0;
	static char temp[200];

	for(i = 0; s[i]; i++)
	{
		if(s[i] != ' ')
		{
			temp[j] = s[i];
			j++;
		}
	}

	temp[j] = '\0';
	return temp;
}

Thanks uhh "wildgoose"
that was simple i guess

Binary size is still the same. I only removed the empty comparison, and the more verbose declaration!

You could use a strtok function to make it smaller if that's allowed!

char *p = strtok( s, " " );
*temp = 0;

while (NULL != p)
{
    strcat( temp, p );
     p = strtok( NULL, " " );
}

But that's really no smaller then what you already had and in fact will run slower because of the overhead of the strtok and the strcat!